Timeline for How does lowering resistance lead to lower IR drop if the current will increase as a result?

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Nov 6, 2023 at 9:32	comment	added	Fredled		Yes, I agree with you. I only suggested another experiment in addition to it.
Nov 6, 2023 at 0:05	comment	added	Noxet		@Fredled It is not negilible. In your own example, you used a 1M resistor. Many DMMs have an internal resistance of 10M. With that, you would read around 4.5V.. But, again, why not just measure over a resistor, wouldn't that be more pedagogical to show that they have a "drop"?
Nov 5, 2023 at 23:51	comment	added	Fredled		Sure. But the dividing effet of the multi-meter is négligeable, and it's not difficult to take into account this difference. Multi meters are designed to show the most accurate result. Else it would be impossible to work with them on electronic circuits.
Nov 5, 2023 at 23:45	comment	added	Noxet		@Fredled But now you have created a voltage divider with the multimeter.. You would not (in any case besides when the resistor is 0 Ohms) read 5 V. I fail to see the point here tbh
Nov 4, 2023 at 21:33	comment	added	Fredled		The closed loop is implemented by the two multi meter probes. (The red one on the resistor output and the black on GND.)
Nov 4, 2023 at 13:09	comment	added	Noxet		@Fredled Not sure what your point is, but if you disconnect the resistors from GND, you will measure 0V across them.. you need a closed loop for any voltage drop to occur
Nov 3, 2023 at 23:56	comment	added	Fredled		Ine way to understand that resistors have a voltage drop equal to100% f the supplied voltage is to disconnect them from the GND and measure the voltage with a multi meter. Even 1M would show 5V. This is because no energy is consumed. Once you connect a load, the voltage is reduced accordingly.
Nov 3, 2023 at 23:12	history	answered	Noxet	CC BY-SA 4.0