Timeline for How do basic voltage drop calculations work?
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
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| Nov 10, 2023 at 3:23 | comment | added | Simon Fitch | @Fredrick Done. | |
| Nov 10, 2023 at 3:22 | history | edited | Simon Fitch | CC BY-SA 4.0 |
Update
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| Nov 9, 2023 at 16:42 | comment | added | Fredrick | Sure you can, meanwhile I'll try to work it out | |
| Nov 9, 2023 at 16:38 | comment | added | Simon Fitch | @Fredrick I think the best way to show that would be to derive a general formula for voltage across a resistor in such scenarios. I'll add that to my answer when I have a moment. | |
| Nov 9, 2023 at 15:36 | comment | added | Fredrick | That's seems interesting, how does the current involve itself without being shown to be actively involved? | |
| Nov 8, 2023 at 1:35 | comment | added | Simon Fitch | @Fredrick To me the most interesting thing is that it doesn't matter what the resistances are, as long as they are equal, they will always share the battery voltage equally between them, effectively "dividing by two"; 100Ω + 100Ω, or 47kΩ + 47kΩ would have that same effect. This is regardless of the current that flows around the loop, suggesting that current has nothing to do with it, but "behind the scenes" current is intimately involved. | |
| Nov 7, 2023 at 18:18 | comment | added | Fredrick | Also another thing to notice, the power supplied to the single 10 ohm is 10 W (due to 10 V x 1 A), but the power supplied to the combination of the two resistors 10 ohm and 10 ohm with 0.5 A and 5 V drop combined is 2.5 W + 2.5 W = 5 W. That's half the power loss! | |
| Nov 7, 2023 at 18:07 | comment | added | Fredrick | That's really a comprehensive answer. I totally got your explanation! | |
| Nov 7, 2023 at 17:32 | history | edited | Simon Fitch | CC BY-SA 4.0 |
deleted 9 characters in body
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| Nov 7, 2023 at 17:31 | vote | accept | Fredrick | ||
| Nov 7, 2023 at 17:31 | vote | accept | Fredrick | ||
| Nov 7, 2023 at 17:31 | |||||
| Nov 7, 2023 at 17:27 | history | answered | Simon Fitch | CC BY-SA 4.0 |