Timeline for Antenna tuning and L/C matching
Current License: CC BY-SA 4.0
9 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Jan 9 at 23:28 | vote | accept | George kirby | ||
Jan 9 at 14:01 | comment | added | Andy aka | @Georgekirby the matching network will improve the power to the antenna but, as I said in my 3rd bullet point in my answer, the Q-factor of the matching network may restrict the usable bandwidth of the signals transmitted to the antenna. Also, because the antenna may not be an ideal quarter wave dipole (for instance) the radiation shape may be affected; the power will still be transmitted but, the lobe shapes (in extreme cases) may make the antenna not as one might want it. If you need more detail on how this might pan out, I suggest you ask a new question and get other contributors involved. | |
Jan 9 at 12:59 | comment | added | George kirby | Have done, hopefully clearer | |
Jan 5 at 23:48 | comment | added | Andy aka | @Georgekirby please rephrase your question because I'm getting confused by it (it's late in the evening round here so I may not reply till tomorrow) | |
Jan 5 at 22:20 | comment | added | George kirby | I see that makes sense, on the second note Apologies when i said 0 real resistance i mean the part that isnt its ‘radiation resistance’, as in, when for example the antenna is not at its resonant frequency, but there is a matching network in place to prevent reflections, where does the non propagated energy go? | |
Jan 5 at 22:09 | comment | added | Andy aka | @Georgekirby I used 37 ohm as the value of radiation resistance because, an ideal monopole antenna actually and theoretically has this value. You then match the 37 ohm of the antenna to the feedline (probably 50 ohm). Ideal matching means minimal loss. For an antenna to be valid it must present a radiation resistance to the electrical terminals or, power doesn't get transmitted and will be wholly reflected. | |
Jan 5 at 21:53 | comment | added | George kirby | Thankyou for the straightforward responses. So i would assume in the 1/4 monopole case, the most optimum solution for a 50ohm receiver/emmiter is to match the 37 to to 50 at said frequency, and I would assume assuming ideal matching there would be no loss in doing so? Also what about if the antenna had 0 real resistance, but wasnt at a naturall frequency, where does that transmitted power go? Thanks | |
Jan 5 at 21:18 | history | edited | Andy aka | CC BY-SA 4.0 |
added 604 characters in body
|
Jan 5 at 21:03 | history | answered | Andy aka | CC BY-SA 4.0 |