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S Mar 16 at 19:41 history suggested Alex CC BY-SA 4.0
Add picture of working FIR and explain solution
Mar 16 at 10:39 review Suggested edits
S Mar 16 at 19:41
Mar 13 at 13:59 comment added Im Groot result of (coeff * 2^23-1) will have both integer and fractional bit se we have to apply rounding to get rid of the fractional part. Now what's left will have our desired fixed point number with 0 floating bits.
Mar 13 at 13:12 comment added Alex Thanks for your answer. You wrote "Convert the floating-point coefficients to fixed-point format. Just multiplying each coefficient by the scaling factor" Would this represent a fixed-point format with 0 fractional bits?
Mar 13 at 12:33 history edited Im Groot CC BY-SA 4.0
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Mar 13 at 12:24 history answered Im Groot CC BY-SA 4.0