Timeline for Why are CC1 and CC2 only connected to USB-C?
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
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| Mar 26 at 23:46 | comment | added | euraad | @比尔盖子 No, I know what I'm doing. That's why I choose a 3.5mm DC plug connector instead. | |
| Mar 25 at 12:49 | comment | added | 比尔盖子 | @euraad Furthermore, if you only need to power a basic device from 5 V 500 mA from USB-C, you don't need to understand any of the implementation details involved. Simply attaching two 56 kΩ resistors on the CC pins, and you're done. Anything else is left as an exercise for the power supply makers. How is that confusing? This reason alone is my personal reason to use USB-C for random circuit prototype. No more "can't find cables" headaches. | |
| Mar 25 at 12:28 | comment | added | 比尔盖子 | @euraad You must be lucky enough to never have the experience of trying to figure out a compatible DC jack among a bunch of incompatible DC cables and connectors with millimeters differences, or trying to figure out what DC voltage is accepted by the device, or trying to figure out it's center-positive or center-negative, or trying to solder something onto a PCB but accidentally melting a piece of fragile plastic DC jack, or... Do you? The point of USB-C is a practical one, cables and standard and common with a reasonable metal plug. | |
| Mar 25 at 9:08 | comment | added | AnoE | @euraad, you can of course build whichever connection you wish. Read the specs of your DC connector/cable; if it is sufficient for your use case, then it is perfectly valid to use it. There is no reason to overcomplicate it if you need none of the features of the USB-C solution. This does not make USB-C more or less relevant (nor DC connectors). They both have their good uses. Obviously, do not use a USB jack on the one side of a cable and a DC jack on the other side. | |
| Mar 24 at 23:44 | comment | added | euraad | A DC plug can deliver more than 1 amps. But if I want to have 5V from a source, I don't actually need that schematic with the USB-C connection? I could use a regular DC plug instead? I'm going to build that computer. | |
| Mar 24 at 19:45 | comment | added | Justme | The USB-C connector likely is specified to last more mating sequences and deliver more power, than a random DC plug or jack. @Kubahasn'tforgottenMonica Not only because power is off while plugging. It also prevents you from plugging two power supplies accidentally together and end up with damaged equipment. | |
| Mar 24 at 18:30 | comment | added | euraad | @Kubahasn'tforgottenMonica Yes, the circuit is a mini-computer made of STM32MP157 processor. But is there any issues by using 3.5 DC connector instead? Way more simplier. | |
| Mar 24 at 17:22 | comment | added | Kuba hasn't forgotten Monica | @euraad Why confusing? How can two resistors be confusing? Surely the circuit you are powering is more complex than that? The idea with USB-C is that to prolong the life of the connector, no hot plugging happens. That is, when you make or break the connection, the supply current is off. That is accomplished by having the CC connection break first when unplugging, and make last when connecting. | |
| Mar 24 at 16:40 | vote | accept | euraad | ||
| Mar 24 at 16:02 | comment | added | euraad | It seems very confusing to use USB-C as a power device. Much better to use a regular jack-in DC connector. | |
| Mar 24 at 15:57 | comment | added | Chester Gillon | @euraad I have tried to update the answer to address your comment. | |
| Mar 24 at 15:57 | history | edited | Chester Gillon | CC BY-SA 4.0 |
Add information about state of CCx pins on the power sink in response to a comment
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| Mar 24 at 15:44 | comment | added | euraad | So is CC2 and CC1 going low or high? | |
| Mar 24 at 14:22 | history | answered | Chester Gillon | CC BY-SA 4.0 |