Timeline for Polarized capacitor on AC circuit
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| May 31 at 4:02 | comment | added | MOSFET | @MichaelPingol Another idea: think about putting the 9V battery where the transformer is instead. Evaluate the circuit. Now flip the battery. Re-evaluate the circuit with the new polarity. The AC analysis here really is just two DC evaluations. In fact, this is exactly the analysis for the case where the AC is a square wave. | |
| May 31 at 3:58 | comment | added | MOSFET | @MichaelPingol No. The AC will not discharge the capacitor. The only thing in the whole circuit that will discharge the capacitor is the push switch. That LED is a diode, and that's the only capacitor path when the switch is open. It will "block" the reverse AC voltage. AC is really just "DC in a moment of time". In other words, just consider the AC as 2 DC parts [in time]. You have +9DC for the first moment in time and you have -9V for the second moment. That's how you can evaluate the circuit - a DC circuit but consider both polarities. | |
| May 31 at 3:44 | comment | added | Michael Pingol | i understand the DC part of this schematic and i know from what i learned so far that this capacitor is not powering the LED when discharging because the LED is on reverse biased. my only concern is the AC part will it charge and discharge the capacitor when the current goes to the positive part since AC is alternating its polarity. | |
| May 31 at 3:40 | vote | accept | Michael Pingol | ||
| May 31 at 2:55 | history | answered | MOSFET | CC BY-SA 4.0 |