Timeline for how does ESR change as dielectric barrier increases?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Jul 7 at 21:23 | comment | added | Hearth | @JosephSummerhays There may be a minuscule adjustment to the ESR from the additional bus length needed to connect the plates to the now-slightly-more-distant leads/termination, but that would be a truly tiny correction. | |
| Jul 7 at 21:17 | vote | accept | Joseph Summerhays | ||
| Jul 7 at 21:13 | comment | added | Hearth | @JosephSummerhays What I stated still holds. The ESR, particularly at low frequencies, is a property primarily of the metallic parts of the capacitor alone, and what you've described doesn't alter the metallic parts. Now, if you stated you were making the plates thinner to fit more dielectric, that would be another matter, but the implication (as I read it) was that you're just moving the plates further apart. | |
| Jul 7 at 21:07 | comment | added | Joseph Summerhays | If only the dielectric is twice as large, the overall capacitor might not have changed much at all. Often the dielectric is the minority of the space in the capacitor. Supposing doubling the voltage in this case makes practically no difference in the package size, will the ESR remain the same? | |
| Jul 7 at 20:54 | history | answered | Hearth | CC BY-SA 4.0 |