The Vbe of the transistor will be about 0.7V so you can expect the base current to be roughly (5V-0.7V)/470Ω = 9.1mA. Since the base current is relatively high Vbe might be higher, and it might be a bit less, depending on the transistor. If it's a small type like 2N3904 it will definitely be much less since Vbe will be closer to 900mV.

Let's do a CircuitLab simulation with a power transistor TIP41:

^{simulate this circuit – Schematic created using CircuitLab}

Now the transistor had better have a pretty good heat sink or it will die in this configuration since it's dissipating >5W.

Also Vbe will drop as the transistor heats, this is indicative of what would typically happen with a real TIP41 in this circuit for the first brief period after power is applied.

To predict the Vbe from the datasheet, there are curves, but for normal saturated switching operation, which don't exactly apply in your situation with the transistor out of saturation:

As you can see the predicted Vbe in saturated condition and 9mA Ib is around 50mV less than the simulated solution out of saturation. Still pretty close though.

The Vbe of the transistor will be about 0.7V so you can expect the base current to be roughly (5V-0.7V)/470Ω = 9.1mA. Since the base current is relatively high Vbe might be higher, and therefore the current might be a bit less, depending on the transistor. If it's a small type like 2N3904 it will definitely be much less Ib than 9.1mA since Vbe will be closer to 900mV.

Let's do a CircuitLab simulation with a power transistor TIP41:

^{simulate this circuit – Schematic created using CircuitLab}

Now the transistor had better have a pretty good heat sink or it will die in this configuration since it's dissipating >5W.

Also Vbe will drop as the transistor heats, this is indicative of what would typically happen with a real TIP41 in this circuit for the first brief period after power is applied.

To predict the Vbe from the datasheet, there are curves, but for normal saturated switching operation, which don't exactly apply in your situation with the transistor out of saturation:

As you can see the predicted Vbe in saturated condition and 9mA Ib is around 50mV less than the simulated solution out of saturation. Still pretty close though.

The Vbe of the transistor will be about 0.7V so you can expect the base current to be roughly (5V-0.7V)/470Ω = 9.1mA. Since the base current is relatively high Vbe might be higher, and it might be a bit less, depending on the transistor. If it's a small type like 2N3904 it will definitely be much less since Vbe will be closer to 900mV.

Let's do a CircuitLab simulation with a power transistor TIP41:

^{simulate this circuit – Schematic created using CircuitLab}

Now the transistor had better have a pretty good heat sink or it will die in this configuration since it's dissipating >5W.

Also Vbe will drop as the transistor heats, this is indicative of what would typically happen with a real TIP41 in this circuit for the first brief period after power is applied.

The Vbe of the transistor will be about 0.7V so you can expect the base current to be roughly (5V-0.7V)/470Ω = 9.1mA. Since the base current is relatively high Vbe might be higher, and it might be a bit less, depending on the transistor. If it's a small type like 2N3904 it will definitely be much less since Vbe will be closer to 900mV.

Let's do a CircuitLab simulation with a power transistor TIP41:

^{simulate this circuit – Schematic created using CircuitLab}

Now the transistor had better have a pretty good heat sink or it will die in this configuration since it's dissipating >5W.

Also Vbe will drop as the transistor heats, this is indicative of what would typically happen with a real TIP41 in this circuit for the first brief period after power is applied.

To predict the Vbe from the datasheet, there are curves, but for normal saturated switching operation, which don't exactly apply in your situation with the transistor out of saturation:

As you can see the predicted Vbe in saturated condition and 9mA Ib is around 50mV less than the simulated solution out of saturation. Still pretty close though.