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19 hours ago comment added greybeard "You can of course add two 4-bit numbers in a single clock cycle [combinatorically]" (or "single level" of delay) This necessitates two 9-input LUTs for sum MSB and carry out.
yesterday comment added shafe I think I see what you're saying. In the above diagram where there's only 1 arrow leading from the adaptive LUT to either adder, there really are 2 bits going to each full adder (4 bits total) then correct? And the adders combine the combinatorial outputs with the carry bits?
yesterday history answered Marcus Müller CC BY-SA 4.0