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pipe
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An s-curve pot is not simply achieved by adding resistors unfortunately. An inverse s-curve pot is easy to do. See see this articlethis article right at the end for an example - it mistakingly calls it an "s-curve" but it means an "inverse-s curve".

Just so you are sure, please check if you need an s-curve or an inverse-s curve

This is the curve you get when you have a 100k pot with fixed resistors (100k and 50k) from both ends meeting at the wiper: -

enter image description here

The vertical axis is \$ V_{out} / V_{in} \$ where \$ V_{in} \$ is applied across the pot and \$ V_{out} \$ is wiper to common connection of input

No matter what value of fixed resistors you choose the curve will be inverse S. Using a log pot won't help either - it'll still be an inverse S but biased towards the top of the graph.

An s-curve pot is not simply achieved by adding resistors unfortunately. An inverse s-curve pot is easy to do. see this article right at the end for an example - it mistakingly calls it an "s-curve" but it means an "inverse-s curve".

Just so you are sure, please check if you need an s-curve or an inverse-s curve

This is the curve you get when you have a 100k pot with fixed resistors (100k and 50k) from both ends meeting at the wiper: -

enter image description here

The vertical axis is \$ V_{out} / V_{in} \$ where \$ V_{in} \$ is applied across the pot and \$ V_{out} \$ is wiper to common connection of input

No matter what value of fixed resistors you choose the curve will be inverse S. Using a log pot won't help either - it'll still be an inverse S but biased towards the top of the graph.

An s-curve pot is not simply achieved by adding resistors unfortunately. An inverse s-curve pot is easy to do. See this article right at the end for an example - it mistakingly calls it an "s-curve" but it means an "inverse-s curve".

Just so you are sure, please check if you need an s-curve or an inverse-s curve

This is the curve you get when you have a 100k pot with fixed resistors (100k and 50k) from both ends meeting at the wiper:

enter image description here

The vertical axis is \$ V_{out} / V_{in} \$ where \$ V_{in} \$ is applied across the pot and \$ V_{out} \$ is wiper to common connection of input

No matter what value of fixed resistors you choose the curve will be inverse S. Using a log pot won't help either - it'll still be an inverse S but biased towards the top of the graph.

added graph
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Andy aka
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  • 839

An s-curve pot is not simply achieved by adding resistors unfortunately. An inverse s-curve pot is easy to do. see this article right at the end for an example - it mistakingly calls it an "s-curve" but it means an "inverse-s curve".

Just so you are sure, please check if you need an s-curve or an inverse-s curve

This is the curve you get when you have a 100k pot with fixed resistors (100k and 50k) from both ends meeting at the wiper: -

enter image description here

The vertical axis is \$ V_{out} / V_{in} \$ where \$ V_{in} \$ is applied across the pot and \$ V_{out} \$ is wiper to common connection of input

No matter what value of fixed resistors you choose the curve will be inverse S. Using a log pot won't help either - it'll still be an inverse S but biased towards the top of the graph.

An s-curve pot is not simply achieved by adding resistors unfortunately. An inverse s-curve pot is easy to do. see this article right at the end for an example - it mistakingly calls it an "s-curve" but it means an "inverse-s curve".

Just so you are sure, please check if you need an s-curve or an inverse-s curve

An s-curve pot is not simply achieved by adding resistors unfortunately. An inverse s-curve pot is easy to do. see this article right at the end for an example - it mistakingly calls it an "s-curve" but it means an "inverse-s curve".

Just so you are sure, please check if you need an s-curve or an inverse-s curve

This is the curve you get when you have a 100k pot with fixed resistors (100k and 50k) from both ends meeting at the wiper: -

enter image description here

The vertical axis is \$ V_{out} / V_{in} \$ where \$ V_{in} \$ is applied across the pot and \$ V_{out} \$ is wiper to common connection of input

No matter what value of fixed resistors you choose the curve will be inverse S. Using a log pot won't help either - it'll still be an inverse S but biased towards the top of the graph.

Source Link
Andy aka
  • 473.1k
  • 29
  • 383
  • 839

An s-curve pot is not simply achieved by adding resistors unfortunately. An inverse s-curve pot is easy to do. see this article right at the end for an example - it mistakingly calls it an "s-curve" but it means an "inverse-s curve".

Just so you are sure, please check if you need an s-curve or an inverse-s curve