Timeline for Finding current using Kirchoff Law, but getting unsolvable system
Current License: CC BY-SA 3.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 3, 2023 at 18:58 | answer | added | Antonio51 | timeline score: 0 | |
| May 26, 2016 at 3:25 | answer | added | sidt36 | timeline score: 1 | |
| Sep 21, 2013 at 1:07 | history | edited | roverred | CC BY-SA 3.0 |
added 157 characters in body
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| Sep 21, 2013 at 1:03 | vote | accept | roverred | ||
| Sep 20, 2013 at 11:11 | comment | added | Iancovici | I'd recommend combining 1st and 4th equation, treat the voltage source branch as a supernode | |
| Sep 20, 2013 at 10:41 | comment | added | Scott Seidman | There are quite a few more KVL loops available for you to add | |
| Sep 20, 2013 at 9:42 | answer | added | helloworld922 | timeline score: 4 | |
| Sep 20, 2013 at 9:16 | history | tweeted | twitter.com/#!/StackElectronix/status/380983843467304960 | ||
| Sep 20, 2013 at 9:13 | comment | added | Dor | I think you need to simplify the circuit and then use a wye-delta transform to make it solvable easily: en.wikipedia.org/wiki/Y-%CE%94_transform | |
| Sep 20, 2013 at 8:42 | answer | added | geniass | timeline score: 1 | |
| Sep 20, 2013 at 8:26 | comment | added | travisbartley | Its still not a solvable system of linear equations after that correction. | |
| Sep 20, 2013 at 7:59 | review | First posts | |||
| Sep 20, 2013 at 8:00 | |||||
| Sep 20, 2013 at 7:57 | comment | added | markrages | Shouldn't "\$12I_4\$" be "\$6I_4\$" in your 5th equation? | |
| Sep 20, 2013 at 7:43 | history | asked | roverred | CC BY-SA 3.0 |