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Jun 16, 2016 at 18:20 comment added Mark Main TI has a great paper on this, section 1.3 has the formulas and full explanation is provided throughout the document. http://www.ti.com.cn/cn/lit/an/slta055/slta055.pdf
Oct 1, 2013 at 4:31 vote accept Dabloons
Oct 1, 2013 at 3:12 answer added The Photon timeline score: 18
Sep 30, 2013 at 22:41 history edited Gustavo Litovsky CC BY-SA 3.0
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Sep 30, 2013 at 21:16 history tweeted twitter.com/#!/StackElectronix/status/384788978693857281
Sep 30, 2013 at 20:53 comment added Ignacio Vazquez-Abrams cypress.com/?rID=12873
Sep 30, 2013 at 20:04 comment added Andy aka @Dabloons - Listen to the man
Sep 30, 2013 at 19:36 comment added Scott Winder The voltage regulator cannot respond instantaneously to changes in power requirements, resulting in a momentary dip in voltage when current demands increase. The capacitors charge to the output voltage level of the regulator, and then supply localized current while the regulator adjusts to meet the demands on the power rail. The capacitors are placed as near as possible to the current sink to minimize the resistive effects of the trace (or wire) connecting the IC to the supply.
Sep 30, 2013 at 19:27 comment added dext0rb Those capacitors are called decoupling/bypass capacitors. Decoupling = isolate from noise, bypass = provide local energy for when fast switching digital signals require it.
Sep 30, 2013 at 19:18 comment added Shabab First of all, I'm too low on reputation to comment. All whining aside, could you post your design IC name and links to the datasheets you're using? I've seen often that the IC design recommends components (some go as specific as the component maker). Did your datasheet not include this? If you could post a few additional details, such as part number, PCB layout/schematic, components you would like to use, I think you could get more specific answers.
Sep 30, 2013 at 18:54 history asked Dabloons CC BY-SA 3.0