0
\$\begingroup\$

I was trying to understand the way this problem was solved and I got confused with the latter part of the solution. I encircled the part that confused me. They seem to contradict each other. If dv(0+)/dt = 0 why is it dv(0+)/dt = -1 in the other one? Please explain. TIA!

enter image description here

enter image description here

enter image description here

enter image description here

\$\endgroup\$

1 Answer 1

0
\$\begingroup\$

It's just a typo. Its obvious from equation 2. They meant: $$\frac{dv_1(0+)}{dt} = \frac{-v_0(0+)}{C_2R_2}=0$$ That's why all \$\frac{dv_1(0+)}{dt}\$ terms vanished from equation 1, on last simplification.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.