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As shown (with no output load) the signal at Vout will not be affected much at all by your RC "equalizer". If you were to place a resistive load from Vout to ground then you would see some frequency dependent response. If you want a good looking square wave at the output consider placing a simple comparator circuit after the AD8010. To limit the frequency response of the AD8010 (and reduce oscillations etc.) also consider placing a small value capacitor across the 10k. The added capacitor would help to give a smooth pulse to the comparator, then the comparator can square up the signal.