Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with amplifier
Search options not deleted
user 142139
An amplifier can be used to adapt the range of a signal to a requirement, to make it more robust for transmission, or to satisfy interface requirements (like input/output impedance).
2
votes
2
answers
398
views
Relation between Output voltage and current in a transresistance amplifier
I need to show that for the above current to voltage converter,
\$\frac{V_0}{i_s} = -R_1(1+\frac{R_3}{R_1}+\frac{R_3}{R_2})\$
assuming that the op-amp is ideal,
Voltage at the negative input …
- 187
1
vote
3
answers
3k
views
Meaning of dB while dealing with amplifier(Op-Amp)
I have found a question in MIT open-course material.The question is to
Design an amplifier(Op-Amp) with a gain of 20dB
While searching about db in the Internet I have found out that 20db is defined … approaches as follows:
From the definition of dB we have: 20dB = 20log(Vout/Vin)
But, from my above searching it should be
20dB = 10log(Vout/Vin)
Moreover the questioner of this question says that db in amplifier …
- 187