Timeline for How can I reduce voltage from 40VDC to 5VDC?
Current License: CC BY-SA 3.0
12 events
when toggle format | what | by | license | comment | |
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Nov 19, 2020 at 4:21 | answer | added | Omid | timeline score: 0 | |
Apr 21, 2014 at 1:06 | vote | accept | cwd | ||
Apr 20, 2014 at 23:55 | answer | added | Aaron D. Marasco | timeline score: -1 | |
Apr 20, 2014 at 23:18 | comment | added | Passerby | The term you want is "Buck" regulator. As opposed to boost regulators which is low to high, or transformer, which is ac to dc. | |
Apr 20, 2014 at 23:03 | answer | added | WhatRoughBeast | timeline score: 4 | |
Apr 20, 2014 at 20:42 | history | tweeted | twitter.com/#!/StackElectronix/status/457982757432721408 | ||
Apr 20, 2014 at 20:17 | answer | added | Mister Mystère | timeline score: 2 | |
Apr 20, 2014 at 20:12 | answer | added | Cornelius | timeline score: 6 | |
Apr 20, 2014 at 20:09 | comment | added | Vladimir Cravero | I believe linear is not an option, 70W is really too much. I don't even know if there are chips that can dissipate that much power, in any case you would need a huge heatsink that adds cost and space. Search for "dc dc step down" on rs, mouser, digikey or whatever. | |
Apr 20, 2014 at 20:07 | comment | added | cwd | @VladimirCravero - yes, considered it but wasn't sure this was the definitive way to go. this is kind of an odd voltage to be coming from. so you're saying linear is one option but it is pretty inefficient / lots of waste? reason for 50/40 - two possible voltage sources one is ~40VDC and one is ~50VDC - still need to get to 5VDC either way | |
Apr 20, 2014 at 20:05 | comment | added | Vladimir Cravero | did you consider using a switching DC-DC step down regulator? I think this is a must because also if you don't mention it, a linear regulator would dissipate as much as 70W, give or take some. And that's an awful lot. Curiosity: how comes you have this 40~50Vdc? What is your application? | |
Apr 20, 2014 at 20:01 | history | asked | cwd | CC BY-SA 3.0 |