Timeline for bjt biasing and applying input signal
Current License: CC BY-SA 3.0
12 events
when toggle format | what | by | license | comment | |
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Apr 23, 2014 at 9:12 | answer | added | Anklon | timeline score: 0 | |
Apr 23, 2014 at 8:50 | answer | added | Anklon | timeline score: 0 | |
Apr 23, 2014 at 8:11 | answer | added | LvW | timeline score: 1 | |
Apr 23, 2014 at 8:03 | comment | added | Andy aka | It'll make the 2nd figure work but no, the two figures cannot be perfectly equivalent. | |
Apr 23, 2014 at 8:02 | comment | added | Vladimir Cravero | nope. in the first picture the dc component of \$V_B\$ is the dc component of the \$V_i\$, in the second one it's "decided" by \$R_{B1}\$ and \$R_{B2}\$. | |
Apr 23, 2014 at 7:32 | comment | added | user40754 | Now, if I add the coupling capacitor in the second one does that make the two figures equivalent? @LvW | |
Apr 23, 2014 at 7:28 | comment | added | user40754 | Sorry, consider the coupling capacitor, I forgot. | |
Apr 23, 2014 at 6:47 | comment | added | LvW | Without a coupling capacitor the resistor Rb2 will be shorted and there will be no proper dc biasing. | |
Apr 23, 2014 at 6:17 | review | First posts | |||
Apr 23, 2014 at 6:48 | |||||
Apr 23, 2014 at 6:15 | comment | added | jippie | The answer is in the part that I suspect you erased from the picture, the coupling capacitor. | |
Apr 23, 2014 at 6:03 | comment | added | user40754 | Are the two figures equivalent? | |
Apr 23, 2014 at 6:02 | history | asked | user40754 | CC BY-SA 3.0 |