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sparky Al
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If I rectify 10Vac (rms) by diodes without a voltage drop to a full wave pulsating dc, the peak voltage would be Vrms x square root of 2 = 14.142135V The dc (average) voltage would be

2V peak/pi = 9.00316V,

And the ac voltage would be 4.35236V (the rms value of the ripple)

I have adjusted the supply voltage to get 9.003V on the Vdc voltmeter.

To get rid of the voltage drop over the diodes, I am measuring the AC through 2 diodes on each polarity. The Multisim measurements are different from mine, and since they are also calculated, I wonder what formulas they use.

edited: I have made the actual circuit and have measured with 3 different multimeters. They came closer to the calculated values than the multisim.

I have scaled it up to reduce error. For 100Vac (after diodes voltage drop) sine wave, the Vdc (average) was 90.5, and AC measured 42V. (for 10V rms,.. Vdc = 9.05, .. vac = 4.2)

multisim for 10Vrms had: Vcd = 8.83, and for Vac =4.62

enter image description here

If I rectify 10Vac (rms) by diodes without a voltage drop to a full wave pulsating dc, the peak voltage would be Vrms x square root of 2 = 14.142135V The dc (average) voltage would be

2V peak/pi = 9.00316V,

And the ac voltage would be 4.35236V (the rms value of the ripple)

I have adjusted the supply voltage to get 9.003V on the Vdc voltmeter.

To get rid of the voltage drop over the diodes, I am measuring the AC through 2 diodes on each polarity. The Multisim measurements are different from mine, and since they are also calculated, I wonder what formulas they use.

enter image description here

If I rectify 10Vac (rms) by diodes without a voltage drop to a full wave pulsating dc, the peak voltage would be Vrms x square root of 2 = 14.142135V The dc (average) voltage would be

2V peak/pi = 9.00316V,

And the ac voltage would be 4.35236V (the rms value of the ripple)

I have adjusted the supply voltage to get 9.003V on the Vdc voltmeter.

To get rid of the voltage drop over the diodes, I am measuring the AC through 2 diodes on each polarity. The Multisim measurements are different from mine, and since they are also calculated, I wonder what formulas they use.

edited: I have made the actual circuit and have measured with 3 different multimeters. They came closer to the calculated values than the multisim.

I have scaled it up to reduce error. For 100Vac (after diodes voltage drop) sine wave, the Vdc (average) was 90.5, and AC measured 42V. (for 10V rms,.. Vdc = 9.05, .. vac = 4.2)

multisim for 10Vrms had: Vcd = 8.83, and for Vac =4.62

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sparky Al
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enter image description here

If I rectify 10Vac (rms) by diodes without a voltage drop to a full wave pulsating dc, Thethe peak voltage would be Vrms x square root of 2 = 14.142135V The dc (average) voltage would be

2V peak/pi = 9.00316V,

And the ac voltage would be 4.35236V (the rms value of the ripple)

I have adjusted the supply voltage to get 9.003V on the Vdc voltmeter.

To get rid of the voltage drop over the diodes, I am measuring the AC through 2 diodes on each polarity. The Multisim measurements are different from mine, and since they are also calculated, I wonder what formulas they use.

enter image description here

If I rectify 10Vac (rms) by diodes without a voltage drop to a full wave pulsating dc, The peak voltage would be Vrms x square root of 2 = 14.142135V The dc (average) voltage would be

2V peak/pi = 9.00316V,

And the ac voltage would be 4.35236V (the rms value of the ripple)

I have adjusted the supply voltage to get 9.003V on the Vdc voltmeter.

To get rid of the voltage drop over the diodes, I am measuring the AC through 2 diodes on each polarity. The Multisim measurements are different from mine, and since they are also calculated, I wonder what formulas they use.

enter image description here

If I rectify 10Vac (rms) by diodes without a voltage drop to a full wave pulsating dc, the peak voltage would be Vrms x square root of 2 = 14.142135V The dc (average) voltage would be

2V peak/pi = 9.00316V,

And the ac voltage would be 4.35236V (the rms value of the ripple)

I have adjusted the supply voltage to get 9.003V on the Vdc voltmeter.

To get rid of the voltage drop over the diodes, I am measuring the AC through 2 diodes on each polarity. The Multisim measurements are different from mine, and since they are also calculated, I wonder what formulas they use.

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sparky Al
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How does Multisim calculate voltages?

enter image description here

If I rectify 10Vac (rms) by diodes without a voltage drop to a full wave pulsating dc, The peak voltage would be Vrms x square root of 2 = 14.142135V The dc (average) voltage would be

2V peak/pi = 9.00316V,

And the ac voltage would be 4.35236V (the rms value of the ripple)

I have adjusted the supply voltage to get 9.003V on the Vdc voltmeter.

To get rid of the voltage drop over the diodes, I am measuring the AC through 2 diodes on each polarity. The Multisim measurements are different from mine, and since they are also calculated, I wonder what formulas they use.