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Apr 5, 2015 at 22:22 comment added vlad_tepesch @SeanBoddy yes - a very rough aproximated sinus ;-). i added a little diagram. the frequency should be variable by a small amount, but the original frequency of the motor is 50Hz. The duty cycle i meant is the ratio of both phases on-time to the complete cycle (the above example has 75%). 100% does mean that one channel is the complete inverted of the other and both channels has a 50% dut cycle pwm
Apr 5, 2015 at 22:14 history edited vlad_tepesch CC BY-SA 3.0
added pulse diagram
Apr 5, 2015 at 8:52 answer added user39962 timeline score: 2
Apr 5, 2015 at 8:50 answer added Andy aka timeline score: 2
Apr 5, 2015 at 8:47 comment added user39962 Wait, are you using a fixed frequency, fixed duty cycle signal to power this motor?
Apr 5, 2015 at 8:43 comment added vlad_tepesch me neither thatswhy i am asking ;) My knowledge mainly is in the digital domain.
Apr 5, 2015 at 8:23 comment added Vladimir Cravero low pass the square wave with an LC filter then. that's not really something I'm an expert of, sorry
Apr 5, 2015 at 8:14 comment added vlad_tepesch and yes i also assume that it is the square wave. i hoped the inductance of the motor and a small ceramic cap would smooth it out enough. but it does not seem to work.
Apr 5, 2015 at 8:10 comment added vlad_tepesch i tried the 100nF. with larger values i only have electrolytes that may not fit since the alternating polarities.
Apr 5, 2015 at 8:08 comment added Vladimir Cravero I am guessing that the problem lies in the square wave you are feeding it now. Try to put a... 1uF cap in parallel with your motor. Try also 100nF that might be better.
Apr 5, 2015 at 8:03 history asked vlad_tepesch CC BY-SA 3.0