Timeline for Gain of filter is higher than calculated - why?
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 12, 2017 at 9:27 | answer | added | Verbal Kint | timeline score: 4 | |
| Jul 9, 2015 at 19:06 | history | edited | imulsion | CC BY-SA 3.0 |
added 241 characters in body
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| Jul 9, 2015 at 19:01 | comment | added | imulsion | @AdamDavis of course | |
| Jul 9, 2015 at 18:49 | comment | added | Adam Davis | Even though you've received an answer, this is a good question and will help others in the future. Would you mind including the specific formula you used, as well as the calculated result that led to the 1.5 gain? | |
| Jul 9, 2015 at 18:00 | vote | accept | imulsion | ||
| Jul 9, 2015 at 16:24 | history | tweeted | twitter.com/#!/StackElectronix/status/619180359352197121 | ||
| Jul 9, 2015 at 12:51 | comment | added | user16324 | He may mean impedances in series and parallel : in which case if he linearly added instead of remembering the 90 degree phase shift and taking the hypotenuse ... | |
| Jul 9, 2015 at 12:28 | answer | added | LvW | timeline score: 6 | |
| Jul 9, 2015 at 11:40 | comment | added | user207421 | Where did you get 1.5 from? Leaving the capacitors aside, say around 5kHz, the gain is 68/33, assuming also you have a zero input impedance source and a reasonable load impedance. And what do series/parallel resistance formulae have to do with it? | |
| Jul 9, 2015 at 11:00 | answer | added | Andy aka | timeline score: 3 | |
| Jul 9, 2015 at 10:26 | history | asked | imulsion | CC BY-SA 3.0 |