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Feb 9, 2017 at 8:53 vote accept Vedanshu
Jan 20, 2017 at 15:18 answer added Andy aka timeline score: 0
Jan 20, 2017 at 12:09 answer added GNA timeline score: 0
Jan 20, 2017 at 10:51 comment added Claudio Avi Chami You could also ask what would be the equation of a switch shortcutting a power source. V/0 -> infinite current
Jan 20, 2017 at 10:50 comment added Claudio Avi Chami That is the problem when you suppose that there are ideal elements. An ideal capacitor CANNOT be connected to an ideal voltage source because the resultant current would be infinite. In reality there would be a very high current or even it could happen a puncture of the capacitor.
Jan 20, 2017 at 10:49 comment added Curd As I said: in practicy there is always some resistance. Therefore current will not be infinte and charging time will be >0. So voltage change will be in practice not "suddenly".
Jan 20, 2017 at 10:47 comment added Vedanshu That means capacitor will be charged within a very short time, to the source voltage; doesn't that changes the property of capacitor of sudden change in voltage, "capacitor does not allow sudden change in voltage across it" ?
Jan 20, 2017 at 10:44 comment added Curd In ideal case (R=0) current will be infinite for an infinitely short time after switching on. In practice there will be some resistance R and you'll get a \$I(t)=I_0e^{-\frac{t}{RC}}\$ where \$I_0=\frac{Vs}{R}\$.
Jan 20, 2017 at 10:41 comment added Vedanshu What will be the nature of current ?
Jan 20, 2017 at 10:32 comment added Curd If there is not resistance (also no internal resistane in the voltage source, switch or capacitor) there is not much of an equation.... i.e. the equation is \$V_C(t)=0\$ for \$t<0\$ and \$V_C(t)=V_s\$ for \$t>0\$
Jan 20, 2017 at 10:29 history asked Vedanshu CC BY-SA 3.0