Timeline for Circuit Analysis
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 26, 2017 at 21:23 | answer | added | dannyf | timeline score: -1 | |
| Apr 26, 2017 at 21:15 | vote | accept | hfbroady | ||
| Apr 26, 2017 at 21:05 | answer | added | TonyM | timeline score: 1 | |
| Apr 26, 2017 at 21:03 | comment | added | hfbroady | @curd. Yeah that is the voltage at V3 -2.904V is coming from a +12V to -3V regulator. Sorry if I placed the voltage source incorrectly. | |
| Apr 26, 2017 at 21:03 | comment | added | Voltage Spike♦ | @Curd, I was thinking the same thing | |
| Apr 26, 2017 at 20:59 | comment | added | Curd | are you sure V3 is -2.904V? That means the voltage at the terminal connected to R2 is +2.904V! | |
| Apr 26, 2017 at 20:52 | answer | added | jonk | timeline score: 1 | |
| Apr 26, 2017 at 20:45 | history | edited | hfbroady | CC BY-SA 3.0 |
added 4 characters in body
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| Apr 26, 2017 at 20:29 | answer | added | Voltage Spike♦ | timeline score: 2 | |
| Apr 26, 2017 at 20:23 | comment | added | hfbroady | I did forget a diode on the left leg that connects to ground. With the given values I get Vout as 0.268V when I measure it with a DMM. | |
| Apr 26, 2017 at 20:22 | history | edited | hfbroady | CC BY-SA 3.0 |
deleted 2 characters in body
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| Apr 26, 2017 at 20:21 | comment | added | hfbroady | The circuit has been built (not by me) already. This is what I have to work with. | |
| Apr 26, 2017 at 20:21 | comment | added | Enric Blanco | Vout = 0V in your schematic. Is there a resistor missing? | |
| Apr 26, 2017 at 20:20 | comment | added | Voltage Spike♦ | Vout = 0V, you've shorted it | |
| Apr 26, 2017 at 20:20 | comment | added | dandavis | amputate the "left leg" of your circuit and it will work fine. | |
| Apr 26, 2017 at 20:18 | history | asked | hfbroady | CC BY-SA 3.0 |