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Nov 20, 2017 at 15:44 vote accept MaxMil
Nov 17, 2017 at 22:21 answer added jonk timeline score: 3
Nov 17, 2017 at 16:26 comment added MaxMil Yes, I see. But I found that all circuits like this are analyzed with KVL equations first, for example for my: Vcc - Vbe - betta * Ib * (Rc + Re) - Ib * Rf = 0, i. e. 10 - 0.7 - 90*Ib*(4.7k+1.2k) - Ib * 250k = 0. From here I can found Ib. But why that value of Ib in reality must happen? Why when the 10V is applied to schematic the Ib and Ic may not be much smaller (to satisfy Ohms law of course) and stay there?
Nov 17, 2017 at 16:17 comment added Bimpelrekkie To help you think about it: why would it move "randomly about"? I see a clear feedback in the circuit which counteracts (works against) changes in the DC voltage on the collector. Do you see it as well?
Nov 17, 2017 at 16:13 answer added Mitu Raj timeline score: 1
Nov 17, 2017 at 16:07 comment added MaxMil The question was updated to clarify the situation
Nov 17, 2017 at 16:06 history edited MaxMil CC BY-SA 3.0
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Nov 17, 2017 at 16:01 comment added D.A.S. what is negative feedback? think. What is gain ratio of feedback? who does that reduce error?
Nov 17, 2017 at 15:51 history asked MaxMil CC BY-SA 3.0