The question is which logic function does this circuit implement if A and B are input and Y is output?

I'm not familiar how 4-terminal MOSFET works but trying to solve Y using A=0 B= 0

The abovest transistor wouldn't be turned on because \$V_{SG} = 0\$

The belowest transistor also cannot be turned on because \$V_{GS}\$ is negative.

For the transistor having \$V_{DD}\$ at base, which side should we choose as a source?

The question is which logic function does this circuit implement if A and B are input and Y is output?

I'm not familiar how 4-terminal MOSFET works but trying to solve Y using A=0 B= 0

The abovest transistor wouldn't be turned on because \$V_{SG} = 0\$

The belowest transistor also cannot be turned on because \$V_{GS}\$ is negative.

For the transistor having \$V_{DD}\$ at base, which side should we choose as a source?

Edit: I still don't know where to expect source when \$V_{DD}\$ and \$GND\$ are ignored as it is said in the comments. I would appreciate an explanation in solving this.

The question is which logic function does this circuit implement if A and B are input and Y is output?

I'm not familiar how 4-terminal MOSFET works but trying to solve Y using A=0 B= 0

The abovest transistor wouldn't be opened because \$V_{SG} = 0\$

The belowest transistor also cannot be opened because \$V_{GS}\$ is negative.

For the transistor having \$V_{DD}\$ at base, which side should we choose as a source?

The question is which logic function does this circuit implement if A and B are input and Y is output?

I'm not familiar how 4-terminal MOSFET works but trying to solve Y using A=0 B= 0

The abovest transistor wouldn't be turned on because \$V_{SG} = 0\$

The belowest transistor also cannot be turned on because \$V_{GS}\$ is negative.

For the transistor having \$V_{DD}\$ at base, which side should we choose as a source?