Timeline for Is this a proper way to connect a piezo speaker to MCU?
Current License: CC BY-SA 3.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 2, 2015 at 23:24 | answer | added | Simon Tillson | timeline score: 2 | |
| Sep 15, 2012 at 18:15 | vote | accept | miceuz | ||
| Sep 14, 2012 at 3:11 | answer | added | RDeLaPlaza | timeline score: 2 | |
| Sep 13, 2012 at 12:42 | answer | added | Ryan | timeline score: 1 | |
| Sep 5, 2012 at 12:01 | history | tweeted | twitter.com/#!/StackElectronix/status/243317829695315969 | ||
| Sep 5, 2012 at 11:10 | comment | added | Scott Seidman | A TTL piezo buzzer will run about $4.00, so if you're building a one-off its not cost ineffective. Of course, one of your goals might be to learn how to drive a piezo element .... you'll get the loudest buzz if you drive it at resonance | |
| Sep 5, 2012 at 7:22 | comment | added | Christoph B | You can also verify by yourself how this circuit will work using LTspice or whatnot and an equivalent circuit of the piezo buzzer. I'm afraid this particular site doesn't provide any values, but I think you can assume the inductance to be super small, in the sub µH range. With the diode, it won't make a difference anyway :) | |
| Sep 5, 2012 at 7:19 | comment | added | Christoph B | @miceuz: a piezo will create negative voltages in the same sense that a capacitor would. The buzzer might have SOME inductance, which can potentially act as a current source. Your circuit will work just fine, as the diode will take care of the inductance effects. The 1k resistor at the top might not even be necessary. | |
| Sep 5, 2012 at 5:51 | comment | added | miceuz | @ScottSeidman i'm designing with a "dumb" buzzer as the ones with drivers inside tend to be much more expensive, didn't choose a particular part yet | |
| Sep 4, 2012 at 22:06 | comment | added | Scott Seidman | Do you have a part number for the piezo buzzer? Many have driving circuitry built in, and work fine w/ TTL. | |
| Sep 4, 2012 at 21:26 | comment | added | m.Alin | You might be right. But the circuits I've seen either use a resistor or a diode, but not both. | |
| Sep 4, 2012 at 21:22 | comment | added | miceuz | as far as i know, piezos can emit negative voltage spikes when physically hit. on another hand - you use voltage on a piezo - it bends, then it straightens back and emits a spike that is of reverse polarity. | |
| Sep 4, 2012 at 20:45 | history | edited | miceuz | CC BY-SA 3.0 |
spelling fixed
|
| Sep 4, 2012 at 17:42 | history | asked | miceuz | CC BY-SA 3.0 |