I have to find voltage across R₅ using superposition theorem but the problem is that I have a voltage difference of 4.16V,

Solution:-
Shorting battery V_S1

R₃₄ =8/3Ω =2.67Ω (Solved R₃ & R₄ in parallel)
R₂₃₄ =41/3Ω =13.67Ω (Solved R₃₄ & R₂ in series)
R₁₂₃₄ =205/56Ω =3.66Ω (Solved R₂₃₄ & R₁ in parallel)

Using Voltage Divider Formula on R₅
(1)V₅= 6.56V (Voltage when V_S1 is shorted)

Shorting Battery V_S2

R₃₄ =8/3Ω =2.67Ω (Solved R₃ & R₄ in parallel)
R₂₃₄ =41/3Ω =13.67Ω (Solved R₃₄ & R₂ in series)
R₂₃₄₅ =287/62Ω =4.62Ω (Solved R₃ & R₄ in parallel)

Using Voltage Divider Formula on R₂₃₄₅
Therefore, (2)V₅=V₂₃₄₅= 2.40V(Voltage when V_S2 is shorted)

Since the flow of voltage is opposite on R₅ the resultant voltage(V₅) can be obtained by taking the difference of the voltages obtained by shorting the batteries.
Resultant V₅ =(1)V₅ - (2)V₅
Resultant V₅ = 6.56 - 2.40
Resultant V₅ = 4.16V
x------------------------------------------------------------x--------------------------------------------------------------------x

According to my solution after taking the difference at the end I'm obtaining a value of 4.16V of V₅ but according to the given answer it says that the answer is 2.40V. I want to know that if there is something wrong with my solution or the answer provided is wrong?.

I have to find voltage across R₅ using superposition theorem but the problem is that I have a voltage difference of 4.16V,

Solution:-
Shorting battery V_S1

R₃₄ =8/3Ω =2.67Ω (Solved R₃ & R₄ in parallel)
R₂₃₄ =41/3Ω =13.67Ω (Solved R₃₄ & R₂ in series)
R₁₂₃₄ =205/56Ω =3.66Ω (Solved R₂₃₄ & R₁ in parallel)

Using Voltage Divider Formula on R₅
(1)V₅= 6.56V (Voltage when V_S1 is shorted)

Shorting Battery V_S2

R₃₄ =8/3Ω =2.67Ω (Solved R₃ & R₄ in parallel)
R₂₃₄ =41/3Ω =13.67Ω (Solved R₃₄ & R₂ in series)
R₂₃₄₅ =287/62Ω =4.62Ω (Solved R₂₃₄ & R₅ in parallel)

Using Voltage Divider Formula on R₂₃₄₅
Therefore, (2)V₅=V₂₃₄₅= 2.40V(Voltage when V_S2 is shorted)

Since the flow of voltage is opposite on R₅ the resultant voltage(V₅) can be obtained by taking the difference of the voltages obtained by shorting the batteries.
Resultant V₅ =(1)V₅ - (2)V₅
Resultant V₅ = 6.56 - 2.40
Resultant V₅ = 4.16V
x------------------------------------------------------------x--------------------------------------------------------------------x

According to my solution after taking the difference at the end I'm obtaining a value of 4.16V of V₅ but according to the given answer it says that the answer is 2.40V. I want to know that if there is something wrong with my solution or the answer provided is wrong?.