Timeline for Connecting Solenoid valve in the emitter of the transistor
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
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| Jan 2, 2021 at 18:01 | comment | added | TapasX | Thanks, now I completely got it. When connecting load across emitter and the ground: The VBE required to maintain the forward bias will go away as voltage will drop across the load. If VBE is set at 0.7 V, and then as soon as the voltage across load becomes 0.7V transistor will no longer act as a switch. As their will not be potential difference across VBE. Thanks Circuit fantasist (Cyril Mechkov) for giving correct reply. | |
| Jun 3, 2020 at 20:08 | comment | added | TapasX | Solenoid valve is working fine. When using proportional valve using PWM, I am facing difficulty. Extension of this post, here.tinyurl.com/y7g3xwu8 | |
| Jun 1, 2020 at 6:06 | comment | added | Circuit fantasist | A controller output (port) should be used to drive the transistor. Also, connect a backward biased diode in parallel to the coil (against the self induced emf in the coil). | |
| Jun 1, 2020 at 5:42 | comment | added | TapasX | Load should be connected between the collector and 24 V supply rail, this should be true for while giving PWM input to the base to the TIP 122 (Transistor) via resistor. | |
| Jun 1, 2020 at 5:28 | vote | accept | TapasX | ||
| Jun 1, 2020 at 4:12 | comment | added | Circuit fantasist | The solenoid has low coil resistance; so, it should be connected in series to the transistor - for the first case, between the collector and 24 V; for the second case, between the emitter and ground. Then: 1. For the first case, the whole 24 V voltage will be applied across the load. 2. For the second case, only the difference between the input voltage and base-emitter voltage will be applied across the load (which is only 3.3 - 1.4 = 1.9 V). Hence point 1 makes sense, which is load should be connected between the collector and 24 V supply rail. I have added more explanations to my answer. | |
| Jun 1, 2020 at 4:06 | history | edited | Circuit fantasist | CC BY-SA 4.0 |
Structured text
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| Jun 1, 2020 at 2:18 | comment | added | TapasX | Understanding from your answer. 1. For the first case voltage across collector and emitter will be applied across the load. 2. For the second case the voltage of the base emitter voltage will be applied across the load (which is very less), Hence point 1, make sense, which is load should be connected across the collector end of the transistor. | |
| May 31, 2020 at 19:54 | history | edited | Circuit fantasist | CC BY-SA 4.0 |
Minor edit
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| May 31, 2020 at 19:34 | history | edited | Circuit fantasist | CC BY-SA 4.0 |
About the voltage across the load
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| May 31, 2020 at 19:27 | history | edited | Circuit fantasist | CC BY-SA 4.0 |
Specified voltage drop
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| May 31, 2020 at 19:22 | history | edited | Circuit fantasist | CC BY-SA 4.0 |
Added note
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| May 31, 2020 at 19:10 | history | edited | Circuit fantasist | CC BY-SA 4.0 |
Added final
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| May 31, 2020 at 19:05 | history | answered | Circuit fantasist | CC BY-SA 4.0 |