Timeline for NOT gate power consumption
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 14, 2020 at 9:59 | comment | added | Telmo Marques | Also happy to see that the wikipedia article was corrected en.wikipedia.org/wiki/Inverter_(logic_gate) | |
| Aug 14, 2020 at 9:57 | vote | accept | Telmo Marques | ||
| Aug 13, 2020 at 16:24 | answer | added | The Photon | timeline score: 5 | |
| Aug 13, 2020 at 15:06 | comment | added | D.A.S. | All transistors are inverting when used as switches. Single switches need a pull-up which defines the risetime into say 30pF load so you can choose the R value accordingly. Complementary switches only draw leakage when the other is off, so CMOS has ana advantage yet provide low impedance fast rise times. | |
| Aug 13, 2020 at 14:59 | comment | added | Chris Stratton | Someone clueless vandalized wikipedia. A FET transistor being "on" means very little in terms of power consumption unless it has a load drawing current. In CMOS that would be other insulated FET gates which have no path for steady current, so CMOS can be very nearly thought of as only drawing power when switching. Drastically less power over time than your circuit above. | |
| Aug 13, 2020 at 14:58 | comment | added | user16324 | Somebody needs to correct that Wikipedia entry. | |
| Aug 13, 2020 at 14:53 | comment | added | Telmo Marques | @BrianDrummond I previously checked wikipedia and found this: "(CMOS) greatly increases power consumption since one of the transistors is always off in both logic states." Could you please clarify? en.wikipedia.org/wiki/Inverter_(logic_gate) | |
| Aug 13, 2020 at 14:52 | comment | added | Telmo Marques | I've edited the question, I was less interested in the rate of discharge and more weather any discharge would happen or not. | |
| Aug 13, 2020 at 14:47 | history | edited | Telmo Marques | CC BY-SA 4.0 |
added 13 characters in body
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| Aug 13, 2020 at 14:46 | comment | added | user16324 | Yes for a suitable definition of "quick". If R1 = R2 = 1 Megohm, Vcc = 5V, and the input is '1' half the time, you're looking at 5 microamps (assuming the load is high impedance). And there are alternatives where R1 is replaced by another transistor, and you make sure only one transistor is on at once. (aka "totem pole" and CMOS) | |
| Aug 13, 2020 at 14:43 | comment | added | StainlessSteelRat | Depends on the values of R1 and power is only consumed when transistor is ON. | |
| Aug 13, 2020 at 14:39 | history | asked | Telmo Marques | CC BY-SA 4.0 |