Timeline for Is it possible for series connected battery cells to provide different currents?
Current License: CC BY-SA 4.0
19 events
| when toggle format | what | by | license | comment | |
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| Sep 28, 2020 at 20:38 | comment | added | PLL | @PeteBecker: Equally, though, it’s important to remind people that you can wire up batteries in a way that looks in series, but may not really be electrically in series due to leakage or similar reasons. That’s (as I read it) why jonk’s comment had the caveat about leakage. | |
| Sep 28, 2020 at 17:11 | comment | added | Robert Crovella | Kirchhoff's Current Law. | |
| Sep 28, 2020 at 16:23 | comment | added | Pete Becker | The question is about batteries in series. My point is that introducing sneak paths means that they are not in series. That seems to me an easier way for a beginner to think about this issue than thinking that they're in series but there's leakage. | |
| Sep 28, 2020 at 16:19 | comment | added | jonk | @PeteBecker I'm not one to argue words when we both know the same situation equally well and don't need words. But things can be both in series and in parallel. In this case, it would be a series set of batteries with parallel leakage. So I'm not sure why you care or even want to bother with "they aren't in series" with me. Was there some purpose? | |
| Sep 28, 2020 at 16:06 | comment | added | Pete Becker | @jonk -- if "you have some leakage around them" they aren't in series. | |
| Sep 27, 2020 at 10:56 | answer | added | simon coleman | timeline score: 3 | |
| Sep 27, 2020 at 8:28 | comment | added | fraxinus | BMS systems state per-cell current because cells are sometimes connected in parallel or in mixed configurations. | |
| Sep 27, 2020 at 6:00 | history | tweeted | twitter.com/StackElectronix/status/1310096857142644739 | ||
| Sep 27, 2020 at 5:06 | history | became hot network question | |||
| Sep 27, 2020 at 5:00 | answer | added | troubleshooter | timeline score: 8 | |
| Sep 26, 2020 at 22:03 | comment | added | jonk | @N.Berg I just did a quick calculation to illustrate. If you string up a silver wire from the moon to the earth, whose cross-section totaled just 1 cm^2, and you could arrange for a constant voltage difference between the ends of 1 GV (easily doable), then in one century's time you'd have enough charge difference between the earth and moon to completely cancel out their entire mutual gravitational attraction. | |
| Sep 26, 2020 at 21:44 | answer | added | Scott Seidman | timeline score: 4 | |
| Sep 26, 2020 at 21:37 | answer | added | Circuit fantasist | timeline score: 3 | |
| Sep 26, 2020 at 21:36 | answer | added | Moty | timeline score: 2 | |
| Sep 26, 2020 at 21:25 | vote | accept | N. Berg | ||
| Sep 26, 2020 at 21:15 | answer | added | Barry | timeline score: 17 | |
| Sep 26, 2020 at 21:14 | comment | added | jonk | No, if the batteries are in series then the currents through them will be the same (unless you have some leakage around them for some reason.) The universe pretty much insists that nodes between batteries do not collect charges for any useful length of time. The forces are very much larger than you can imagine. Small charge differences could quite literally be used to move the moon away from the Earth. They are unimaginably powerful. | |
| Sep 26, 2020 at 21:13 | comment | added | Circuit fantasist | "It is possible for one supply to provide more or less current than another series supply" but since the current through them is the same, I think it would be determined (limited) by the "weakest" supply. | |
| Sep 26, 2020 at 21:06 | history | asked | N. Berg | CC BY-SA 4.0 |