Timeline for How to calculate maximum input power on a speaker?
Current License: CC BY-SA 4.0
11 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Nov 30, 2020 at 18:00 | history | tweeted | twitter.com/StackElectronix/status/1333470882266755073 | ||
Nov 30, 2020 at 8:54 | history | became hot network question | |||
Nov 30, 2020 at 8:45 | answer | added | Frog | timeline score: 1 | |
Nov 30, 2020 at 0:57 | answer | added | Math Keeps Me Busy | timeline score: 4 | |
Nov 30, 2020 at 0:25 | answer | added | Jerry Coffin | timeline score: 14 | |
Nov 29, 2020 at 23:50 | answer | added | Elliot Alderson | timeline score: 0 | |
Nov 29, 2020 at 23:46 | comment | added | Math Keeps Me Busy | Calculate the current in your speakers. \$I=\sqrt{\frac{P}{R}}\$ = \$\sqrt{\frac{140W}{8\Omega}} = 4.183A\$. The wires need to handle this current. The voltage is immaterial to the current carrying capacity of a wire. | |
Nov 29, 2020 at 23:44 | comment | added | Finbarr | "so I wanted wires that would not exceed 140W" - not quite sure what your thinking is here. | |
Nov 29, 2020 at 23:38 | comment | added | Hearth | First off, 120 volts sounds like a ton to drive a speaker with. Are you sure that's the output voltage? Secondly, also bear in mind that the impedance of the speaker is going to vary with frequency, it'll only be 8 Ω at one or two specific frequencies. | |
Nov 29, 2020 at 23:33 | review | First posts | |||
Dec 9, 2020 at 10:55 | |||||
Nov 29, 2020 at 23:31 | history | asked | lief | CC BY-SA 4.0 |