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Left closed in review as "Original close reason(s) were not resolved" by Voltage Spike♦
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I have a device that says it takes a 23A, 12V"23A 12V" battery. I ordered a new battery and was mistakenly sent one with 27A and 12V -a "27A 12V" battery; same voltage, higher current. Is it safe to use this battery in the device, or will it break things?

Apologies for what must seem like a noob question; I'm not an electronics person. I have found a very similar question but it talks about capacity instead, and I'm not 100% sure whether that changes the answer or not.

I have a device that says it takes a 23A, 12V battery. I ordered a new battery and was mistakenly sent one with 27A and 12V - same voltage, higher current. Is it safe to use this battery in the device, or will it break things?

Apologies for what must seem like a noob question; I'm not an electronics person. I have found a very similar question but it talks about capacity instead, and I'm not 100% sure whether that changes the answer or not.

I have a device that says it takes a "23A 12V" battery. I ordered a new battery and was mistakenly sent a "27A 12V" battery; same voltage, higher current. Is it safe to use this battery in the device, or will it break things?

Apologies for what must seem like a noob question; I'm not an electronics person. I have found a very similar question but it talks about capacity instead, and I'm not 100% sure whether that changes the answer or not.

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Can I Is it safe to use batteries with a higher-than-recommended current27A battery instead of a 23A battery in my doorbell?

Left closed in review as "Original close reason(s) were not resolved" by Voltage Spike♦
Post Closed as "Duplicate" by RoyC, user80875, PeterJ, Bence Kaulics, Andy aka
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Can I use batteries with a higher-than-recommended current?

I have a device that says it takes a 23A, 12V battery. I ordered a new battery and was mistakenly sent one with 27A and 12V - same voltage, higher current. Is it safe to use this battery in the device, or will it break things?

Apologies for what must seem like a noob question; I'm not an electronics person. I have found a very similar question but it talks about capacity instead, and I'm not 100% sure whether that changes the answer or not.