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Mar 16, 2021 at 12:16 comment added user16324 Because C27 and C12 are both grounded. Thus C9/D1/C27 are in parallel with the tuned circuit, allowing D1 to affect its resonant frequency.
Mar 16, 2021 at 11:58 review Close votes
Mar 31, 2021 at 3:03
Mar 16, 2021 at 4:21 comment added Hearth That is an abysmally drawn schematic!
Mar 16, 2021 at 3:33 comment added mmmm And the price for the most crowdedly drawn schematic goes to.... I'm mentally redrawing parts of this schematic just to get an idea of how it would look weren't pixels so darn expensive! This is really unnecessarily hard to understand. This is no critique of your question, just a note that things might generally be easier to understand for you if the authors of schematics try less hard to cram as many schematic symbols as possible into small space.
Mar 16, 2021 at 2:25 history edited apoch CC BY-SA 4.0
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Mar 16, 2021 at 2:23 history undeleted apoch
Mar 16, 2021 at 2:22 history deleted apoch via Vote
Mar 16, 2021 at 2:20 review First posts
Mar 16, 2021 at 6:00
Mar 16, 2021 at 2:19 history asked apoch CC BY-SA 4.0