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Miss Mulan
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Suppose we have this circuit:

schematicschematic

simulate this circuitsimulate this circuit – Schematic created using CircuitLab

Z = 4-3j

I = V/Z = 1<0/5<36 = 0.2< -36 A

But when I use Ohm's law on the capacitor i get this which doesn't make any sense:

Vc = IZc = 0.2< -36 -3j = 0.2< -36 *3< -90 = 0.6< -126.

Any help appreciated

Suppose we have this circuit:

schematic

simulate this circuit – Schematic created using CircuitLab

Z = 4-3j

I = V/Z = 1<0/5<36 = 0.2< -36 A

But when I use Ohm's law on the capacitor i get this which doesn't make any sense:

Vc = IZc = 0.2< -36 -3j = 0.2< -36 *3< -90 = 0.6< -126.

Any help appreciated

Suppose we have this circuit:

schematic

simulate this circuit – Schematic created using CircuitLab

Z = 4-3j

I = V/Z = 1<0/5<36 = 0.2< -36 A

But when I use Ohm's law on the capacitor i get this which doesn't make any sense:

Vc = IZc = 0.2< -36 -3j = 0.2< -36 *3< -90 = 0.6< -126.

Any help appreciated

Source Link
Miss Mulan
  • 1
  • 1
  • 5
  • 15

AC circuit capacitor voltage drop

Suppose we have this circuit:

schematic

simulate this circuit – Schematic created using CircuitLab

Z = 4-3j

I = V/Z = 1<0/5<36 = 0.2< -36 A

But when I use Ohm's law on the capacitor i get this which doesn't make any sense:

Vc = IZc = 0.2< -36 -3j = 0.2< -36 *3< -90 = 0.6< -126.

Any help appreciated