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Aug 9, 2021 at 7:35 comment added winny By globe, I would hazard a guess that you are from Australia?
Aug 9, 2021 at 3:18 answer added jay timeline score: 0
Aug 9, 2021 at 3:00 answer added D.A.S. timeline score: 1
Aug 9, 2021 at 1:16 comment added Drew A LC filter might work, but the required inductance could be excessive.
Aug 9, 2021 at 1:06 comment added jonk If you multiply the pulse duration (in seconds) by the pulse current (in amps) you will get Coulombs. You can divide into that, the maximum voltage rise you can tolerate before the LEDs show something, to get a capacitance value: \$C=\frac{\Delta Q}{\Delta V}\$. Whether or not that's a useful value (and how to hook everything up, besides) is another issue. I'm not savvy about these auto circuits, and you've not posted something I could read to become educated about it either, so I'm not going to be much help beyond that.
Aug 9, 2021 at 1:05 review First posts
Aug 9, 2021 at 9:33
Aug 9, 2021 at 1:00 history asked James D CC BY-SA 4.0