Timeline for Second order active high pass filter
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 24, 2022 at 4:12 | comment | added | Jing Hao Siet | Thank You guys so much for the help. This seem like different ways to write the transfer function. It is indeed a different useful pov | |
| May 23, 2022 at 7:24 | history | edited | JRE | CC BY-SA 4.0 |
added 14 characters in body; edited title
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| May 23, 2022 at 5:13 | answer | added | Verbal Kint | timeline score: 3 | |
| May 22, 2022 at 16:26 | answer | added | Antonio51 | timeline score: 3 | |
| May 22, 2022 at 12:44 | answer | added | D.A.S. | timeline score: 3 | |
| May 22, 2022 at 10:02 | review | Close votes | |||
| May 28, 2022 at 3:04 | |||||
| May 22, 2022 at 7:28 | comment | added | D.A.S. | and the topology for those equations is? verbal? j@onk? | |
| May 22, 2022 at 6:24 | comment | added | jonk | \$\omega_{_0}=20\$ and \$\zeta=1\$ and the transfer function is \$1\cdot\frac{s^2}{s^2+2\zeta\omega_{_0} s+\omega_{_0}^2}+\frac12\cdot\frac{2\zeta\omega_{_0} s}{s^2+2\zeta\omega_{_0} s+\omega_{_0}^2}+\frac14\cdot\frac{\omega_{_0}^2}{s^2+2\zeta\omega_{_0} s+\omega_{_0}^2}\$ | |
| May 22, 2022 at 6:15 | comment | added | D.A.S. | Do you see the DC gain of 1/4 and HF gain of 1/2? | |
| May 22, 2022 at 6:14 | comment | added | Verbal Kint | I would first rewrite the transfer function to highlight a dc gain \$G_0\$: divide all the numerator \$N\$ terms by 100 and all the denominator \$D\$ by 400. Then re-arrange the expression in the form of \$G(s)=G_0\frac{1+\frac{s}{\omega_{0N}Q_N}+(\frac{s}{\omega_{0N}})^2}{1+\frac{s}{\omega_{0}Q}+(\frac{s}{\omega_{0}})^2}\$. | |
| S May 22, 2022 at 6:03 | review | First questions | |||
| May 22, 2022 at 12:50 | |||||
| S May 22, 2022 at 6:03 | history | asked | Jing Hao Siet | CC BY-SA 4.0 |