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May 23, 2023 at 11:23 vote accept John Mist
Oct 14, 2022 at 13:02 comment added Lundin Again, you still haven't explained why you must use separate grounds.
Oct 14, 2022 at 5:20 comment added John Mist @Lundin I've already mentioned before that I forgot to put the ground reference of the sensor power source
Oct 13, 2022 at 13:57 comment added Lundin "because the sensor operating voltage is 5-24v" So what? Just do a plain voltage divider. "Both are from different sources" And you can't ground them together because...?
Oct 13, 2022 at 8:06 comment added John Mist @Lundin because the sensor operating voltage is 5-24v and the controller operating voltage is 3.3v. Both are from different sources so.
Oct 13, 2022 at 7:29 comment added Lundin Well, doh... Why do you need isolation?
Oct 13, 2022 at 7:28 comment added John Mist @Lundin to provide isolation between sensor out and controller digital input
Oct 13, 2022 at 6:40 comment added Lundin Why do you need the optocoupler in the first place?
Oct 13, 2022 at 5:10 comment added John Mist yeah I forgot to put the ground reference of sensor power source
Oct 12, 2022 at 16:24 history edited toolic CC BY-SA 4.0
deleted 11 characters in body
Oct 12, 2022 at 16:21 comment added brhans But you have the same GND net connected on both sides of the optocoupler - so it's not isolated.
Oct 12, 2022 at 16:20 history edited brhans CC BY-SA 4.0
added 9 characters in body
Oct 12, 2022 at 15:32 answer added V.V.T timeline score: 0
Oct 12, 2022 at 13:49 comment added John Mist It's just an label. The input is connected from another source.
Oct 12, 2022 at 13:45 comment added Andy aka Your circuit indicates the the input is not isolated.
Oct 12, 2022 at 13:31 answer added DKNguyen timeline score: 1
Oct 12, 2022 at 13:25 history asked John Mist CC BY-SA 4.0