why is the voltage distribution a quarter wavelength out of phase with current in a half wavelength dipole antenna? as show in this photo: https://www.electronics-notes.com/images/antenna-dipole-half-wave-current-voltage-01.svg

It makes sense that in a graph over time, the voltage at the ends of the antenna is a quarter wavelength behind the current measured at the feed. But voltage distribution is over x; isn't the voltage in phase with current over distance?

I was under the impression that at the feed point, current is in phase with voltage. What makes it go 90 degrees out of phase in an antenna?

Why is the voltage distribution a quarter wavelength out of phase with the current in a half-wavelength dipole antenna, as show in this image?

It makes sense that in a graph over time, the voltage at the ends of the antenna is a quarter wavelength behind the current measured at the feed. But voltage distribution is over x; isn't the voltage in phase with current over distance?

I was under the impression that at the feed point, current is in phase with voltage. What makes it go 90° out of phase in an antenna?

why is the voltage distribution a quarter wavelength out of phase with current in a half wavelength dipole antenna? as show in this photo: https://www.electronics-notes.com/images/antenna-dipole-half-wave-current-voltage-01.svg

It makes sense that in a graph over time, the voltage at the ends of the antenna is a quarter wavelength behind the current measured at the feed. But voltage distribution is over x; isn't the voltage in phase with current over distance?

why is the voltage distribution a quarter wavelength out of phase with current in a half wavelength dipole antenna? as show in this photo: https://www.electronics-notes.com/images/antenna-dipole-half-wave-current-voltage-01.svg

It makes sense that in a graph over time, the voltage at the ends of the antenna is a quarter wavelength behind the current measured at the feed. But voltage distribution is over x; isn't the voltage in phase with current over distance?

I was under the impression that at the feed point, current is in phase with voltage. What makes it go 90 degrees out of phase in an antenna?

why is the voltage distribution a quarter wavelength out of phase with current in a half wavelength dipole antenna?

It makes sense that in a graph over time, the voltage at the ends of the antenna is a quarter wavelength behind the current measured at the feed. But voltage distribution is over x; isn't the voltage in phase with current over distance?

why is the voltage distribution a quarter wavelength out of phase with current in a half wavelength dipole antenna? as show in this photo: https://www.electronics-notes.com/images/antenna-dipole-half-wave-current-voltage-01.svg

It makes sense that in a graph over time, the voltage at the ends of the antenna is a quarter wavelength behind the current measured at the feed. But voltage distribution is over x; isn't the voltage in phase with current over distance?