Timeline for How to calculate the average voltage and VRMS of a non sinusoidal waveform [duplicate]
Current License: CC BY-SA 4.0
19 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Jun 25, 2023 at 19:08 | vote | accept | Parstoukas | ||
Jun 15, 2023 at 18:46 | history | left closed in review |
ocrdu toolic Davide Andrea |
Original close reason(s) were not resolved | |
Jun 13, 2023 at 8:37 | history | edited | JRE | CC BY-SA 4.0 |
deleted 46 characters in body
|
Jun 13, 2023 at 8:06 | review | Reopen votes | |||
Jun 15, 2023 at 18:46 | |||||
Jun 13, 2023 at 7:47 | history | closed |
Elliot Alderson Andy aka ac Users with the ac badge or a synonym can single-handedly close ac questions as duplicates and reopen them as needed. |
Duplicate of What does the RMS value of a DC current waveform represent? | |
Jun 13, 2023 at 7:35 | answer | added | Simon Fitch | timeline score: 3 | |
Jun 13, 2023 at 2:14 | comment | added | hacktastical | This is a good answer: electronics.stackexchange.com/questions/648954/… | |
Jun 13, 2023 at 1:31 | answer | added | Mattman944 | timeline score: 2 | |
Jun 13, 2023 at 0:52 | comment | added | DKNguyen | The graph is garbage though. The Y scaling does not match the values given. Four units = 41V but 2 units = -6V? But I do get 12.8V average though. Did not bother to calculate the RMS. | |
Jun 12, 2023 at 21:45 | comment | added | DKNguyen | And calculus should have been a pre-requisite for an electrical engineering program. However you would not have learned the specific expression for average or RMS (especially RMS) in a general calculus course. That should have come up prior to being presented this question in the electrical engineering course. Did the course not tell you how to solve such a problem before throwing it at you? | |
Jun 12, 2023 at 21:40 | comment | added | DKNguyen | I never said you are expected to solve integrals for this question. I specifically said said that you only needed to understand the concept of the integral equations and then count the area under the graph according to what the equations say. As in \$\int_0^T f(x)\$ means the area under the curve f(x) over the interval 0 and T. | |
Jun 12, 2023 at 21:20 | comment | added | Parstoukas | @DKNguyen This is first year of Information and Electrical Engineering, maybe not beginner class, but beginner question because you are not expected to solve the integrals. But I can't figure out how to solve this without them, what do you mean exactly with it comes down to the area under the curve. | |
Jun 12, 2023 at 21:07 | comment | added | DKNguyen | It comes down to area under the curve. The calculus equations with integrals are the same thing but are able to handle graphs you can't figure out the area simply by counting the squares as you can in your example graph. What beginner class is this? Because the question cannot be answered without the concept of integrals as a pre-requisite. You may not need to actually crunch through the equations given that the area under the curve in the question is countable, but you do need to understand the concept of what the equations are saying. | |
Jun 12, 2023 at 20:55 | review | Close votes | |||
Jun 13, 2023 at 7:57 | |||||
Jun 12, 2023 at 20:43 | comment | added | Parstoukas | Just added the given values, as this is a beginner class I feel like the answer should be simpler than these. | |
Jun 12, 2023 at 20:37 | history | edited | Parstoukas | CC BY-SA 4.0 |
added 43 characters in body
|
Jun 12, 2023 at 20:34 | comment | added | periblepsis | I tell you how to do it. But for 75%. It's trivial to re-arrange for any duty cycle, though. Such as 40%. | |
S Jun 12, 2023 at 20:31 | review | First questions | |||
Jun 12, 2023 at 20:53 | |||||
S Jun 12, 2023 at 20:31 | history | asked | Parstoukas | CC BY-SA 4.0 |