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Jun 25, 2023 at 19:08 vote accept Parstoukas
Jun 15, 2023 at 18:46 history left closed in review ocrdu
toolic
Davide Andrea
Original close reason(s) were not resolved
Jun 13, 2023 at 8:37 history edited JRE CC BY-SA 4.0
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Jun 13, 2023 at 8:06 review Reopen votes
Jun 15, 2023 at 18:46
Jun 13, 2023 at 7:47 history closed Elliot Alderson
Andy aka ac
Duplicate of What does the RMS value of a DC current waveform represent?
Jun 13, 2023 at 7:35 answer added Simon Fitch timeline score: 3
Jun 13, 2023 at 2:14 comment added hacktastical This is a good answer: electronics.stackexchange.com/questions/648954/…
Jun 13, 2023 at 1:31 answer added Mattman944 timeline score: 2
Jun 13, 2023 at 0:52 comment added DKNguyen The graph is garbage though. The Y scaling does not match the values given. Four units = 41V but 2 units = -6V? But I do get 12.8V average though. Did not bother to calculate the RMS.
Jun 12, 2023 at 21:45 comment added DKNguyen And calculus should have been a pre-requisite for an electrical engineering program. However you would not have learned the specific expression for average or RMS (especially RMS) in a general calculus course. That should have come up prior to being presented this question in the electrical engineering course. Did the course not tell you how to solve such a problem before throwing it at you?
Jun 12, 2023 at 21:40 comment added DKNguyen I never said you are expected to solve integrals for this question. I specifically said said that you only needed to understand the concept of the integral equations and then count the area under the graph according to what the equations say. As in \$\int_0^T f(x)\$ means the area under the curve f(x) over the interval 0 and T.
Jun 12, 2023 at 21:20 comment added Parstoukas @DKNguyen This is first year of Information and Electrical Engineering, maybe not beginner class, but beginner question because you are not expected to solve the integrals. But I can't figure out how to solve this without them, what do you mean exactly with it comes down to the area under the curve.
Jun 12, 2023 at 21:07 comment added DKNguyen It comes down to area under the curve. The calculus equations with integrals are the same thing but are able to handle graphs you can't figure out the area simply by counting the squares as you can in your example graph. What beginner class is this? Because the question cannot be answered without the concept of integrals as a pre-requisite. You may not need to actually crunch through the equations given that the area under the curve in the question is countable, but you do need to understand the concept of what the equations are saying.
Jun 12, 2023 at 20:55 review Close votes
Jun 13, 2023 at 7:57
Jun 12, 2023 at 20:43 comment added Parstoukas Just added the given values, as this is a beginner class I feel like the answer should be simpler than these.
Jun 12, 2023 at 20:37 history edited Parstoukas CC BY-SA 4.0
added 43 characters in body
Jun 12, 2023 at 20:34 comment added periblepsis I tell you how to do it. But for 75%. It's trivial to re-arrange for any duty cycle, though. Such as 40%.
S Jun 12, 2023 at 20:31 review First questions
Jun 12, 2023 at 20:53
S Jun 12, 2023 at 20:31 history asked Parstoukas CC BY-SA 4.0