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Changed hyperthetical question
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George kirby
George kirby
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I see there are already a few questions asked wether it is better to physcally tune the antenna for said frequency and impedance or use a matching network. It seems the conscenus is often the physical way is prefered firstly. But id like to know exactly why. From my current understanding, the matching network will infact reduce any reflective power due to mismatching, logically then that "not-reflected-power" would lead to more power to the antenna and hence more power to the air? I suspect just because more power is going to the antenna, it is probably wasted in some form and not 100% propagated, so in essence matching a mismatch will always help partly, but just not as if the antenna is actually tuned for that frequency.

So id like to know if im on the right track here, and if so, what actally happensin a case i had matching network to that wastedincrease power that might not get transmitted to free-space (even if thisthe antenna hadsince im not TX at its natural frequency, AND hyperthetically there is no real resistanceohmic loss in the antenna and matching network, would the loss maybenow matched system behave asif it was at its original resonante frequency?

Edit 2: I gather from existing answers in the form of something funnyreality that non relfected power is still going on in the near-feilds to prevent propagation?)be wasted in parastici losses

I see there are already a few questions asked wether it is better to physcally tune the antenna for said frequency and impedance or use a matching network. It seems the conscenus is often the physical way is prefered firstly. But id like to know exactly why. From my current understanding, the matching network will infact reduce any reflective power due to mismatching, logically then that "not-reflected-power" would lead to more power to the antenna and hence more power to the air? I suspect just because more power is going to the antenna, it is probably wasted in some form and not 100% propagated, so in essence matching a mismatch will always help partly, but just not as if the antenna is actually tuned for that frequency.

So id like to know if im on the right track here, and if so, what actally happens to that wasted power that might not get transmitted to free-space (even if this antenna had no real resistance, would the loss maybe in the form of something funny going on in the near-feilds to prevent propagation?)

I see there are already a few questions asked wether it is better to physcally tune the antenna for said frequency and impedance or use a matching network. It seems the conscenus is often the physical way is prefered firstly. But id like to know exactly why. From my current understanding, the matching network will infact reduce any reflective power due to mismatching, logically then that "not-reflected-power" would lead to more power to the antenna and hence more power to the air? I suspect just because more power is going to the antenna, it is probably wasted in some form and not 100% propagated, so in essence matching a mismatch will always help partly, but just not as if the antenna is actually tuned for that frequency.

So id like to know if im on the right track here, and if so, in a case i had matching network to increase power to the antenna since im not TX at its natural frequency, AND hyperthetically there is no ohmic loss in the antenna and matching network, would the now matched system behave asif it was at its original resonante frequency?

Edit 2: I gather from existing answers in reality that non relfected power is still going to be wasted in parastici losses

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George kirby
George kirby
  • 701
  • 2
  • 15

Antenna tuning and L/C matching

I see there are already a few questions asked wether it is better to physcally tune the antenna for said frequency and impedance or use a matching network. It seems the conscenus is often the physical way is prefered firstly. But id like to know exactly why. From my current understanding, the matching network will infact reduce any reflective power due to mismatching, logically then that "not-reflected-power" would lead to more power to the antenna and hence more power to the air? I suspect just because more power is going to the antenna, it is probably wasted in some form and not 100% propagated, so in essence matching a mismatch will always help partly, but just not as if the antenna is actually tuned for that frequency.

So id like to know if im on the right track here, and if so, what actally happens to that wasted power that might not get transmitted to free-space (even if this antenna had no real resistance, would the loss maybe in the form of something funny going on in the near-feilds to prevent propagation?)