Timeline for LTSpice iteration limit reached for operating point simulation of many resistors and power load
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Apr 29 at 15:58 | history | became hot network question | |||
| Apr 29 at 15:40 | answer | added | hennep | timeline score: 0 | |
| Apr 29 at 12:37 | answer | added | Antonio51 | timeline score: 2 | |
| Apr 29 at 8:51 | answer | added | Tim Williams | timeline score: 5 | |
| Apr 29 at 8:36 | comment | added | Ste Kulov |
Try reading this article. You should probably use the LTspice built-in constant power load since it has a built-in mechanism that handles the problem you are seeing (via vprxover parameter).
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| Apr 29 at 8:31 | comment | added | periblepsis |
Let's say there is just R1 and B1. (Perhaps I am failing to understand your circuit -- it happens.) Then the KCL I get is \$\frac{V_{{\text{BRANCH}_1}}}{R_1=127\:\text{m}\Omega}+\frac{12\:\text{W}}{V_{{\text{BRANCH}_1}}}=\frac{12\:\text{V}}{R_1=127\:\text{m}\Omega}\$. This has two positive, real-valued solutions. Not one. That test alone makes me not surprised when simulation problems may arise. There may be more than one stable solution. Not sure why you are finding good results for just one branch. But I don't like the math I see.
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| Apr 29 at 8:22 | history | edited | adamski93 | CC BY-SA 4.0 |
added 114 characters in body
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| Apr 29 at 8:22 | comment | added | adamski93 | I mentioned in the post, I can remove R7 and B7, and the circuit solves correctly. In fact, any it seems to work find up to 6 "branches" and breaks on the 7th one. I have added a screenshot of just 6 branches. | |
| Apr 29 at 7:49 | comment | added | periblepsis | Hmm. Have you tried to remove all of R2..R7 and B2..B7 and just solve it for R1 and B1? Should be simple, right? Please tell me what answer you get for V(BRANCH1). | |
| S Apr 29 at 6:33 | review | First questions | |||
| Apr 29 at 6:47 | |||||
| S Apr 29 at 6:33 | history | asked | adamski93 | CC BY-SA 4.0 |