Timeline for Infinite output impedance in amplifier, instead of 0?
Current License: CC BY-SA 4.0
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| Jul 20 at 19:45 | history | edited | Carl | CC BY-SA 4.0 |
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| Jul 18 at 9:17 | comment | added | Circuit fantasist | ... and should be applied even in your case; otherwise, as I have said above, the op-amp is not an op-amp but a "battery"... | |
| Jul 18 at 9:15 | comment | added | Circuit fantasist | Carl, you cannot connect a constant current source at this place because a conflict occurs between two current sources connected in series (op-amp and Rf is the other current source). Instead, you need to connect a voltage source and vary its voltage by reading the current. In your circuit, the op-amp output voltage will reach the supply voltage, and the op-amp will simply become a "battery". Also, not only RL is the feedback resistor; Rf and more precisely, the combination (voltage divider) Rf and RL forms the negative feedback. Next, "the principle of a virtual short" is always valid... | |
| Jul 17 at 21:36 | history | edited | Carl | CC BY-SA 4.0 |
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| Jul 17 at 21:10 | history | edited | Carl | CC BY-SA 4.0 |
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| Jul 17 at 20:56 | history | answered | Carl | CC BY-SA 4.0 |