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Added insertions about Ohm's law in its two versions
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Circuit fantasist
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Differential vs static resistance

The zero differential resistance Rdiff = dV/dI of voltage sources and the infinite differential resistance of current sources are intrinsic properties, unaffected by whether the circuit is undergoing small-signal or large-signal analysis. These properties are always exhibited as long as there is a change in the input signal; hence the name "differential". At the same time, they have some "static" resistance R = V/I.

Experiments

This can be experimented in a simple way by connecting two different sources - one voltage and the other current - to each other. By varying the quantity produced by one of them, we can determine the differential resistance of the other.

Current source

Let's first supply the load through a current source...

Voltage source as a load: ... and let the load be a voltage source. The static resistance is R = V/I = 1/1 = 1 kΩ. Figuratively speaking, the current source "sees" a 1 kΩ "resistor".

schematic

simulate this circuit – Schematic created using CircuitLab

Because the voltage does not change when the current changes, the differential resistance Rdiff = dV/dI = 0/1 = 0. The current source "sees" an AC short circuit.

STEP 1.1

Resistor load: In this case, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/I = 1 kΩ. The voltage source "sees" a 1 kΩ resistor.

schematic

simulate this circuit

The voltage is proportional to current (Ohm's law).

STEP 1.2

Voltage source

Now let's supply the load through a voltage source...

Current source as a load ... and let the load be a current source. The static resistance is again R = V/I = 1/1 = 1 kΩ. The voltage source "sees" a 1 kΩ "resistor".

schematic

simulate this circuit

Because the current does not change when the voltage changes, the differential resistance Rdiff = dV/dI = 1/0 -> ∞. The voltage source "sees" an AC open circuit.

STEP 2.1

Resistor load: As above, in this case, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/R = 1 kΩ. The voltage source "sees" a 1 kΩ resistor.

schematic

simulate this circuit

The current is proportional to voltage (Ohm's law).

STEP 2.2

Differential vs static resistance

The zero differential resistance Rdiff = dV/dI of voltage sources and the infinite differential resistance of current sources are intrinsic properties, unaffected by whether the circuit is undergoing small-signal or large-signal analysis. These properties are always exhibited as long as there is a change in the input signal; hence the name "differential". At the same time, they have some "static" resistance R = V/I.

Experiments

This can be experimented in a simple way by connecting two different sources - one voltage and the other current - to each other. By varying the quantity produced by one of them, we can determine the differential resistance of the other.

Current source

Let's first supply the load through a current source...

Voltage source as a load: ... and let the load be a voltage source. The static resistance is R = V/I = 1/1 = 1 kΩ. Figuratively speaking, the current source "sees" a 1 kΩ "resistor".

schematic

simulate this circuit – Schematic created using CircuitLab

Because the voltage does not change when the current changes, the differential resistance Rdiff = dV/dI = 0/1 = 0. The current source "sees" an AC short circuit.

STEP 1.1

Resistor load: In this case, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/I = 1 kΩ. The voltage source "sees" a 1 kΩ resistor.

schematic

simulate this circuit

STEP 1.2

Voltage source

Now let's supply the load through a voltage source...

Current source as a load ... and let the load be a current source. The static resistance is again R = V/I = 1/1 = 1 kΩ. The voltage source "sees" a 1 kΩ "resistor".

schematic

simulate this circuit

Because the current does not change when the voltage changes, the differential resistance Rdiff = dV/dI = 1/0 -> ∞. The voltage source "sees" an AC open circuit.

STEP 2.1

Resistor load: As above, in this case, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/R = 1 kΩ. The voltage source "sees" a 1 kΩ resistor.

schematic

simulate this circuit

STEP 2.2

Differential vs static resistance

The zero differential resistance Rdiff = dV/dI of voltage sources and the infinite differential resistance of current sources are intrinsic properties, unaffected by whether the circuit is undergoing small-signal or large-signal analysis. These properties are always exhibited as long as there is a change in the input signal; hence the name "differential". At the same time, they have some "static" resistance R = V/I.

Experiments

This can be experimented in a simple way by connecting two different sources - one voltage and the other current - to each other. By varying the quantity produced by one of them, we can determine the differential resistance of the other.

Current source

Let's first supply the load through a current source...

Voltage source as a load: ... and let the load be a voltage source. The static resistance is R = V/I = 1/1 = 1 kΩ. Figuratively speaking, the current source "sees" a 1 kΩ "resistor".

schematic

simulate this circuit – Schematic created using CircuitLab

Because the voltage does not change when the current changes, the differential resistance Rdiff = dV/dI = 0/1 = 0. The current source "sees" an AC short circuit.

STEP 1.1

Resistor load: In this case, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/I = 1 kΩ. The voltage source "sees" a 1 kΩ resistor.

schematic

simulate this circuit

The voltage is proportional to current (Ohm's law).

STEP 1.2

Voltage source

Now let's supply the load through a voltage source...

Current source as a load ... and let the load be a current source. The static resistance is again R = V/I = 1/1 = 1 kΩ. The voltage source "sees" a 1 kΩ "resistor".

schematic

simulate this circuit

Because the current does not change when the voltage changes, the differential resistance Rdiff = dV/dI = 1/0 -> ∞. The voltage source "sees" an AC open circuit.

STEP 2.1

Resistor load: As above, in this case, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/R = 1 kΩ. The voltage source "sees" a 1 kΩ resistor.

schematic

simulate this circuit

The current is proportional to voltage (Ohm's law).

STEP 2.2

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Circuit fantasist
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  • 71

Differential vs static resistance

The zero differential resistance Rdiff = dV/dI of voltage sources and the infinite differential resistance of current sources are intrinsic properties, unaffected by whether the circuit is undergoing small-signal or large-signal analysis. These properties are always exhibited as long as there is a change in the input signal; hence the name "differential". At the same time, they have some "static" resistance R = V/I.

Experiments

This can be experimented in a simple way by connecting two oppositedifferent sources - one voltage and the other current - to each other. By varying the quantity produced by one of them, we can determine the differential resistance of the other.

Current source

Let's first supply the load through a current source...

Voltage source as a load: ... and let first the load be a voltage source. The static resistance is R = V/I = 1/1 = 1 kΩ. Figuratively speaking, the current source "sees" a 1 kΩ "resistor".

schematic

simulate this circuit – Schematic created using CircuitLab

Because the voltage does not change when the current changes, the differential resistance Rdiff = dV/dI = 0/1 = 0. The current source "sees" an AC short circuit.

STEP 1.1

Resistor load: In thethis case of a resistive load, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/I = 1 kΩ. The voltage source "sees" a 1 kΩ resistor.

schematic

simulate this circuit

STEP 1.2

Voltage source

Now let's supply the load through a voltage source...

Current source as a load ... and let the load be a current source. The static resistance is again R = V/I = 1/1 = 1 kΩ. The voltage source "sees" a 1 kΩ "resistor".

schematic

simulate this circuit

Because the current does not change when the voltage changes, the differential resistance Rdiff = dV/dI = 1/0 -> ∞. The voltage source "sees" an AC open circuit.

STEP 2.1

Resistor load: In theAs above, in this case of a resistive load, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/R = 1 kΩ. The voltage source "sees" a 1 kΩ resistor.

schematic

simulate this circuit

STEP 2.2

Differential vs static resistance

The zero differential resistance Rdiff = dV/dI of voltage sources and the infinite differential resistance of current sources are intrinsic properties, unaffected by whether the circuit is undergoing small-signal or large-signal analysis. These properties are always exhibited as long as there is a change in the input signal; hence the name "differential". At the same time, they have some "static" resistance R = V/I.

Experiments

This can be experimented in a simple way by connecting two opposite sources - one voltage and the other current - to each other.

Current source

Let's first supply the load through a current source...

Voltage source as a load: ... and let first the load be a voltage source. The static resistance is R = V/I = 1/1 = 1 kΩ.

schematic

simulate this circuit – Schematic created using CircuitLab

Because the voltage does not change when the current changes, the differential resistance Rdiff = dV/dI = 0/1 = 0.

STEP 1.1

Resistor load: In the case of a resistive load, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/I = 1 kΩ.

schematic

simulate this circuit

STEP 1.2

Voltage source

Now let's supply the load through a voltage source...

Current source as a load ... and let the load be a current source. The static resistance is again R = V/I = 1/1 = 1 kΩ.

schematic

simulate this circuit

Because the current does not change when the voltage changes, the differential resistance Rdiff = dV/dI = 1/0 -> ∞.

STEP 2.1

Resistor load: In the case of a resistive load, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/R = 1 kΩ.

schematic

simulate this circuit

STEP 2.2

Differential vs static resistance

The zero differential resistance Rdiff = dV/dI of voltage sources and the infinite differential resistance of current sources are intrinsic properties, unaffected by whether the circuit is undergoing small-signal or large-signal analysis. These properties are always exhibited as long as there is a change in the input signal; hence the name "differential". At the same time, they have some "static" resistance R = V/I.

Experiments

This can be experimented in a simple way by connecting two different sources - one voltage and the other current - to each other. By varying the quantity produced by one of them, we can determine the differential resistance of the other.

Current source

Let's first supply the load through a current source...

Voltage source as a load: ... and let the load be a voltage source. The static resistance is R = V/I = 1/1 = 1 kΩ. Figuratively speaking, the current source "sees" a 1 kΩ "resistor".

schematic

simulate this circuit – Schematic created using CircuitLab

Because the voltage does not change when the current changes, the differential resistance Rdiff = dV/dI = 0/1 = 0. The current source "sees" an AC short circuit.

STEP 1.1

Resistor load: In this case, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/I = 1 kΩ. The voltage source "sees" a 1 kΩ resistor.

schematic

simulate this circuit

STEP 1.2

Voltage source

Now let's supply the load through a voltage source...

Current source as a load ... and let the load be a current source. The static resistance is again R = V/I = 1/1 = 1 kΩ. The voltage source "sees" a 1 kΩ "resistor".

schematic

simulate this circuit

Because the current does not change when the voltage changes, the differential resistance Rdiff = dV/dI = 1/0 -> ∞. The voltage source "sees" an AC open circuit.

STEP 2.1

Resistor load: As above, in this case, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/R = 1 kΩ. The voltage source "sees" a 1 kΩ resistor.

schematic

simulate this circuit

STEP 2.2

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Circuit fantasist
  • 19.5k
  • 2
  • 24
  • 71

Differential vs static resistance

The zero differential resistance Rdiff = dV/dI of voltage sources and the infinite differential resistance of current sources are intrinsic properties, unaffected by whether the circuit is undergoing small-signal or large-signal analysis. These properties are always exhibited as long as there is a change in the input signal; hence the name "differential". At the same time, they have some "static" resistance R = V/I.

Experiments

This can be experimented in a simple way by connecting two opposite sources - one voltage and the other current - to each other.

Current source

Let's first supply the load through a current source...

Voltage source as a load: ... and let first the load be a voltage source. The static resistance is R = V/I = 1/1 = 1 kΩ.

schematic

simulate this circuit – Schematic created using CircuitLab

Because the voltage does not change when the current changes, the differential resistance Rdiff = dV/dI = 0/1 = 0.

STEP 1.1

Resistor load: In the case of a resistive load, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/I = 1 kΩ.

schematic

simulate this circuit

STEP 1.2

Voltage source

Now let's supply the load through a voltage source...

Current source as a load ... and let the load be a current source. The static resistance is again R = V/I = 1/1 = 1 kΩ.

schematic

simulate this circuit

Because the current does not change when the voltage changes, the differential resistance Rdiff = dV/dI = 1/0 -> ∞.

STEP 2.1

Resistor load: In the case of a resistive load, the differential resistance is identical to the static resistance - Rdiff = dV/dI = R = V/R = 1 kΩ.

schematic

simulate this circuit

STEP 2.2