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Oct 21 at 10:29 history edited toolic CC BY-SA 4.0
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Oct 21 at 5:58 comment added periblepsis @TomásSalvoAportone You can also use the \$\overline{Q}\$ outputs (if you have them.) For example, if you want the reset startup state to be 9 but the FFs you have are guaranteed only to present 0 at poweron, then use the \$\overline{Q}\$ outputs of the least and most significant FFs of the four FFs being used. Simple enough to do when both Q outputs are available.
Oct 21 at 5:54 comment added periblepsis @SimonFitch That's why you use a 7476 in a discrete system requiring a known power-up state. (As I did when building my first computer in 1974.)
Oct 21 at 5:54 answer added the busybee timeline score: 0
Oct 21 at 5:45 comment added the busybee And even a reproducible initial state of discrete flip-flops may be just a result of the specific circuit.
Oct 21 at 5:28 comment added Simon Fitch Perhaps I spoke to soon, using an FPGA to implement JK flip-flops could guarantee a starting state, since the device will have an initial reset cycle, but discrete flip-flops (such as you'd find in a 7474) do not.
Oct 21 at 5:24 comment added Tomás Salvo Aportone Huh, interesting. Then is my board's display showing a 0 before starting the count because there just isn't an assigned value to Y[3..0] yet? And thanks, learning about this stuff is quite interesting!
Oct 21 at 5:14 comment added Simon Fitch Flip-flops don't have a default value, they can assume any value immediately after power is applied. A simulator may suggest predictability, but real flip-flops have no guaranteed start-up value. That doesn't answer your question, it's just FYI.
Oct 21 at 1:58 history edited Tomás Salvo Aportone CC BY-SA 4.0
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S Oct 21 at 1:56 review First questions
Oct 21 at 6:57
S Oct 21 at 1:56 history asked Tomás Salvo Aportone CC BY-SA 4.0