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Sep 29, 2015 at 3:38 answer added Gabriel Staples timeline score: 3
Sep 29, 2015 at 2:32 comment added Gabriel Staples helloworld922,Looking at Fig 9 in the article linked to by @Brian Plummer, it looks like you're spot-on (I think, as I only did a quick read). It seems to me then that the trigger level on a DSO simply sets the width of that hysteresis band in Fig 9. So,I guess in the case shown (rising edge trigger),no 2nd trigger event can occur until the signal has dropped below the hysteresis band, at which point it becomes eligible for retrigger assuming it then rises again above the trigger level at the top of the band.For falling triggers the band would be above the trigger level, rather than below.
Feb 10, 2014 at 19:29 vote accept JYelton
Feb 7, 2014 at 21:26 answer added Brian Plummer timeline score: 5
Aug 26, 2013 at 18:18 history edited JYelton CC BY-SA 3.0
Improved title
Jul 15, 2013 at 14:09 history tweeted twitter.com/#!/StackElectronix/status/356777520386940929
Jul 15, 2013 at 11:02 answer added Andy aka timeline score: 3
Jul 15, 2013 at 9:59 comment added helloworld922 The tektronix link says: An oscilloscope’s trigger sensitivity determines its ability to react to specified edge trigger conditions over a range of frequencies. This sounds suspiciously like hysteresis used in analog circuits, though I don't know if the two are related.
Jul 15, 2013 at 6:11 comment added JYelton I was able to find a more descriptive article, but I still think some experts at EE.SE could do a better job. :)
Jul 15, 2013 at 6:06 history asked JYelton CC BY-SA 3.0