Above is a transformer with its primary and secondary windings. I just wrote my understanding about a transformer very shorty before my question:
Neglecting losses, we can write the voltage and power unity equations as:
- Vs = (Ns/Np) * Vp
- Vp * Ip = Vs * Is
It seems like; as long as the Vp and (Ns/Np) ratio are the same, whatever the load R is Vs will be the same. Only the current drawn will change.
And if the above argument is true the power dissipated in secondary part is:
Ps = (Vs^2)/R
And if R goes to zero or should I say the secondary winding is shorted, Ps goes to infinity which means this secondary winding would burn.
I have the following questions:
1-) Since there is power unity i.e. Pp = Ps; would that mean if the secondary winding is shorted, would the primary winding burn as well?(I'm asking because the interaction between the windings is electromagnetic which could be a different phenomenon)
2-) If the conclusion is primary winding would burn as well, is that enough to add a fuse to only before the primary winding but not secondary winding?