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As we already know that for an intrinsic semiconductor, the relation between recombination rate (r) and intrinsic carrier concentration (n) is given as the following:

$$r = a \cdot n^2$$

where a: recombination coefficient.

My question is will recombination rate (r) increase or decrease or remain same with doping.

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    \$\begingroup\$ increases with doping \$\endgroup\$
    – User323693
    Commented Jan 22, 2017 at 7:59
  • \$\begingroup\$ will it depend on the dopant. I mean will it increase in both cases where my dopant is a donor or an acceptor. \$\endgroup\$
    – ab29007
    Commented Jan 22, 2017 at 8:05
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    \$\begingroup\$ irrespective of dopant type, unless both types are added to the same intrinsic material \$\endgroup\$
    – User323693
    Commented Jan 22, 2017 at 8:30
  • \$\begingroup\$ thank you very much. you can write it as answer, so I can accept it. \$\endgroup\$
    – ab29007
    Commented Jan 22, 2017 at 8:40
  • \$\begingroup\$ That's fine. Happy learning... \$\endgroup\$
    – User323693
    Commented Jan 22, 2017 at 9:11

1 Answer 1

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undoped

Firstly think about intrinsic semiconductor. When thermal equilibrium satisfied excess holes and electrons are equal. $$n=p$$

Think about electrons at the conduction band. They want to recombine with holes to decreases their energy states.

doped2

When you add donors to semiconductor now there are more electrons want to recombine with fixed holes. Therefore recombination rate must be larger.

All figures are taken Middle East Technical University EE212 Lecture Notes of Prof Dr Cengiz Beşikçi

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