I'm trying to find out what this is and where I can buy one. To me, this looks like a capacitor, but I'm no expert. After using a multimeter, this seems to be the cause for the organ not turning on. (it's an old electric organ that I bought to try to fix) Can someone help me?
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1\$\begingroup\$ That is an electrolytic capacitor. Just like the grey one with 1000mFD on it in the botttom right corner. Electrolytic capacitors are notorious for failing after a while and are often the cause of problems with old power supplies. \$\endgroup\$– OldfartCommented Nov 23, 2019 at 20:29
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\$\begingroup\$ Thanks :) I'm guessing that without soldering it out, I can't tell the milliFarad that this one has? correct? \$\endgroup\$– GB5Commented Nov 23, 2019 at 20:33
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\$\begingroup\$ Welll....l desoldering does seems much easier then removing the heat sink which prevents you seeing the text :-) Don't forget to check the voltage too. \$\endgroup\$– OldfartCommented Nov 23, 2019 at 20:35
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\$\begingroup\$ Thanks for the help and advice !! I appreciate ;) \$\endgroup\$– GB5Commented Nov 23, 2019 at 20:37
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\$\begingroup\$ yes the value is written on part that is not visible \$\endgroup\$– Jasen Слава УкраїніCommented Nov 23, 2019 at 22:33
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1 Answer
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As answered in the comments, it's capacitor and the ratings will be on the side you can't see without removing it. The important question though, is why do you think it's the problem? What tests did you perform? You might be barking up the wrong tree.
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\$\begingroup\$ Correct me If I'm wrong, but using a multimeter, I should be able to see that there is flow between both ends of the capacitor correct? What a did was to check from the beginning to end where the flow stopped, what so far the only spot where that happens is with the capacitor. \$\endgroup\$– GB5Commented Nov 24, 2019 at 2:26
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\$\begingroup\$ Well, sorta. A capacitor for practical purposes does not pass direct current, except for leakage, so depending on exactly how you checked, what you saw may mean nothing. With a capacitor the size this is likely to be, if it were disconnected from the rest of the circuit and you checked it with the ohms setting of your meter, it should show a low (ish) resistance that drifted up to a very high (ish) resistance as it charged. This is much easier to see with an analogue meter, which may not be what you have. If it is dead shorted or dead open you should be able to see that with your multimeter. \$\endgroup\$ Commented Nov 24, 2019 at 17:45