I found a circuit where in the classical Graetz rectifier capacitors were added in parallel to each diode.

It looked something like this:

mysterious rectifier

After the rectifier itself, there was the usual huge capacitor and regulator and so on.

So why the smaller capacitors near the diodes?

  • 51
    \$\begingroup\$ Beautiful CAD output! \$\endgroup\$
    – markrages
    May 13, 2011 at 3:28
  • 7
    \$\begingroup\$ If I hadn't known that was a circuit diagram when I started looking at that it would have taken me a minute to figure out what it was. \$\endgroup\$ May 13, 2011 at 11:00
  • 6
    \$\begingroup\$ @markrages - fuzzy logic, no doubt! \$\endgroup\$
    – stevenvh
    Jul 13, 2011 at 8:43

3 Answers 3


Power supply transformers have leakage inductance and parasitic capacitance, and when the diodes in a bridge rectifier switch off these "non-ideal" elements form a resonant circuit that can oscillate at high frequency. This high frequency oscillation can then couple into the rest of the circuitry. Snubber circuits are used in an attempt to mitigate this problem. Just using capacitors doesn't damp the ringing completely, but does cause it to drop to a lower frequency where the coupling effect is less. An RC circuit across the diodes can damp the ringing almost completely.

You can read more in the following excellent paper: http://www.hagtech.com/pdf/snubber.pdf

  • 6
    \$\begingroup\$ +1 for this excellent answer. Here's another source about how to determine the values of an RC snubber combination across a diode: ridleyengineering.com/snubber.htm \$\endgroup\$
    – zebonaut
    May 13, 2011 at 6:32
  • 4
    \$\begingroup\$ It's fairly common to see capacitors across high-frequency rectifier diodes in power supplies, especially at higher voltages (48V or higher) where you can't get good Schottky rectifiers . The main purpose for the capacitors is to soften the commutation, reducing the amount of EMI generated. \$\endgroup\$ May 13, 2011 at 16:57
  • 1
    \$\begingroup\$ That Ridley page is long gone so here's a copy: web.archive.org/web/20110315065651/http://… \$\endgroup\$
    – Elliot
    Apr 27, 2018 at 15:27

This question has been around for a while,so here's my 2 cents.When converting AC to DC using a full wave bridge,you have 2 diodes on that are conducting and the other 2 that are not conducting,then the AC changes this yields a positive dc and a negative dc,now anytime you turn on and off a diode it has a time period to be fully on or fully off,when you place a small cap across each diode it helps smooth that out,this Idea is to remove it with a small cap,this also make noise riding on the dc,The big cap smoothes some of this out also, The transformer also contributes to this problem of turning the diodes on and off because the secondary is ringing,so the on off signal that we want to get rid of is turning the diode on and off just a little bit,now what fixes almost all of this is a snubber (look for quasimoto)It shows how to adjust the ringing with a circuit that connects to a oscope. It tames ringing to almost nothing,before it gets to the bridge diodes,so it take less capicatance to get a almost flat DC and your diodes can do a better job!


The caps across the diodes are of very small value and they prevent what is called silicone radiation. When the diode cuts off it happens so fast that it generates a radiation which can be picked up by high gain preamp stages of an Amp for example. This can also be seen on direct mains input to the rectifiers where there are no transformers.

  • 2
    \$\begingroup\$ Never heard of "silicone radiation". Do you have a reference? What kind of "radiation" is generated according to this? \$\endgroup\$
    – Rev
    Jun 11, 2015 at 9:40
  • 1
    \$\begingroup\$ "silicone" is the rubbery stuff you use to seal the edges of your bath. "silicon" is the stuff which semiconductors are made of. I don't believe either of them "generates a radiation" though. \$\endgroup\$
    – brhans
    Jun 11, 2015 at 11:47

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.