I am looking at hi-jacking an USB cable to supply to supply > 2.1A to the target. What is the physical current limitations of a standard USB cable?

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    \$\begingroup\$ It can supply hundreds of amps. But not for long. \$\endgroup\$ – CL22 May 13 '15 at 7:56

In July 2012, the USB Promoters Group announced the USB Power Delivery ("PD") specification, an extension that makes use of certified "PD aware" USB cables with standard USB type A and B connectors to deliver up to 2A @ 5v.

In addition to the type A and B cables, the power delivery option will also be part of the new USB-C standard with the reversible connector (like Apple Lightning).

So theoretically you would need to get hold of one of these special PD cables to safely pass 2.1A. Before this, the maximum you could send over a standard USB cable for battery charging was 1.5A @ 5v (and devices not being charged were limited to 100 mA or 500 mA).

The gotcha is I can't find any of these PD-aware cables available for sale.

Standard USB cables use really small wires. Most use 28/28 gauge, meaning 28 gauge for data and 28 gauge for power, because they are designed to handle only 500 mA. 28 gauge is tiny.

Better cables use 28 gauge for data and 24 gauge for power (which is still pretty small). You can search for these using "USB 28/24" in Amazon (without the quotes of course). The same article linked to above claims USB cables with 24 gauge wires can handle 2A, even though that's above the official USB spec of 1.5A. Although come to think of it, I believe a lot of tablets can draw up to 2A when charging.

24 gauge cable has a resistance of 0.0257 Ω/foot, while the resistance of 28 gauge cable is a little over 2.5 times as much. So 2A through a 24 gauge 6-foot cable will drop the voltage 0.3v. Not great, but okay. The same current through a 28 gauge 6-foot cable will drop the voltage 0.77v -- not good.

So it looks like you are probably safe to use a standard USB cable, as long as it is not too long and uses 24 gauge or larger wires.

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    \$\begingroup\$ For a 6 foot 28 gauge usb cable at 2 Amps wouldn't the voltage drop be twice 0.77 Volts since current must flow in both directions, with each wire acting as a resistor? That would make the voltage drop for a 6 foot 28 gauge usb cable 1.56 Volts, not 0.78. Please correct me if I am wrong! \$\endgroup\$ – sudoman Nov 23 '16 at 3:22
  • \$\begingroup\$ Indeed @sudoman comment seem correct. It is easy to make this error, because lab tests are usually performed over single wire over common ground. So for a USB powered device you need to multiply by 2. \$\endgroup\$ – not2qubit Apr 30 '18 at 15:08

I don't think standards matter here. If you are creating a product for sale then yes, you would need to think about conforming to standards. Here, you can do what you like.

The question is really one of how much current can a cable carry and that really depends on: how hot you allow it to get, and what voltage drop across it you can tolerate.

As another posted, hundreds of amps, but not for long. He was joking, but there is some truth in that (may be a few milliseconds!) But you're obviously interested in passing a current for a sustained length of time. What matters is the cross sectional area of the conductors carrying the current. The greater the diameter (the bigger the gauge of wire) the greater is the cross sectional area and the greater the current carrying capacity.

Check this website out:

http://www.solar-wind.co.uk/cable-sizing-DC-cables.html Plug some numbers in and experiment.

The difficult with USB cables is most manufacturers/suppliers don't state the gauge of the power carrying conductors on the inside, but if you can cut the cable you can probably work it out by looking at the size of them.


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