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This is a part of a larger circuit, which will eventually become an SMPS. I can't even seem to get the oscillator to work. The output of the transformer is 12V

The idea here is to supply each individual component in the circuit. If I only supplied one voltage divider, every time a transistor turned on all the current would be sucked to ground.

Here's a diagram for a circuit I know works...

enter image description here

The only difference I can see here is the bottom resistors forming the voltage dividers. I have to keep the input at 12V to avoid using two transformers; this same transformer will later be split into two channels, one an unregulated linear power supply for some motors, and this SMPS for some sensitive control electronics which change load.

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  • \$\begingroup\$ I'm not sure what you are trying to do, but I think what you need is a buffer stage so you don't load the oscillator outputs. \$\endgroup\$
    – jippie
    Commented Jun 20, 2015 at 9:56
  • \$\begingroup\$ An oscillator like this built in Spice will often not start spontaneously because components are perfectly idential. You want to introduce a slight imbalance. \$\endgroup\$
    – jippie
    Commented Jun 20, 2015 at 10:01

1 Answer 1

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  • "which will eventually become an SMPS"

Unless you are thinking of low voltage and low current, DONT TRY TO BUILD YOUR OWN SMPS.

  • "If I only supplied one voltage divider, every time a transistor turned on all the current would be sucked to ground."

I can't imagine what you are talking about, which even more convinces me that you should not be building an SMPS.

  • The only difference I can see here is the bottom resistors forming the voltage dividers.

A difference I see is that you use 1nF instead of 100 nF capacitors, so you frequency would be 100 * higher, which might be a problem.

A big difference is that you seem to want to replace the pull-up resistors by equivalent voltage dividers, presumably because you have a higher power supply than 9V? (You probably don't need to bother, those 2N3904's will wrok well up to much higher voltages.). But you screwed up your calculations: take the leftmost resistors (R1, R2): 500/700 in parallel will act a s a resistor to 9V if you power is 1200/500*9v = 22V, but the equivalent series resistance is ~ 390 Ohm. That probably does not matter much for those resistors, but for R3/R4 it is a big problem.

IME the circuit you show works well without R2/R5 and the diodes. In most cases larger values are choosen for R3/R5, with correspondingly lower capacitor values.

PS I think you approach of taking a know-working circuit and repurposing it for your own projects is fine and can be educational, but you should select a project that is reasonably free feasible and free of danger, and you your theoreticalk knowledge (in this case, calculating the Thevenin equivalent of a voltage divider) should match the level of thinkering you want to do.

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  • \$\begingroup\$ Although it appears my presence here is barely tolerated, I just redid my math and I'm not sure where I'm making the mistake. I'd be much obliged if you'd join me in chat...chat.stackexchange.com/rooms/25029/… \$\endgroup\$
    – Allenph
    Commented Jun 20, 2015 at 10:10

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